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jarptica [38.1K]
3 years ago
11

Explain one way world war ii?-era advances in computers

Computers and Technology
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer: It forced almost the whole world to advance in computers and other technology.    

Explanation: When WWII started everyone had there older computers but when country's got destroyed, along with millions killed. It sparked a revolution, which lead to many new inventions such as the ATM, but also a huge advance in computers and technology.

You might be interested in
Was LDAP version2 an internet standard in 1998? is it now?
mamaluj [8]

Answer Explanation:

LDAP stand for lightweight directory access protocol 389 is its port number it is an application layer protocol it was first invented in march 1998 and become very popular widespread  internet standard in august 1998 its authentication method is very simple the client send user name and password to LDAP server to access this.

4 0
3 years ago
Write a code that calculates the Greatest Common Divisor (GCD) of two positive integers (user-defined inputs). Include an except
STALIN [3.7K]

Answer:

<em>This program is written using Java programming language</em>

import java.util.*;

public class calcGcd

{

   public static void main (String [] args)

   {

       int num1, num2;

       Scanner input = new Scanner(System.in);

       //Input two integers

       num1 = input.nextInt();

       num2 = input.nextInt();

       //Get least of the two integers

       int least = num1;

       if(num1 > num2)

       {

           least = num2;

       }

       //Initialize gcd to 1

       int gcd = 1;

       //Calculate gcd using for loop

       for(int i=1;i<=least;i++)

       {

           if(num1%i == 0 && num2%i == 0)

           {

               gcd = i;

           }

       }

       if(gcd == 1)

       {

           System.out.print("GCD is 1");

       }

       else

       {

           System.out.print("GCD is "+gcd);

       }

   }

}

Explanation:

To calculate the GCD, the program uses a for loop that iterates from 1 to the smaller number of the user input.

Within this iteration, the program checks for a common divisor of the two user inputs by the iterating element

The GCD is then displayed afterwards;

However, if the GCD is 1; the program prints the message "GCD is 1"

<em>Line by Line Explanation</em>

This line declares two integer numbers

       int num1, num2;

This line allows user the program to accept user defined inputs        

Scanner input = new Scanner(System.in);

The next two line allows gets inputs from the user

<em>        num1 = input.nextInt();</em>

<em>        num2 = input.nextInt();</em>

<em />

To calculate the GCD, the smaller of the two numbers is needed. The smaller number is derived using the following if statement

<em>        int least = num1;</em>

<em>        if(num1 > num2)</em>

<em>        {</em>

<em>            least = num2;</em>

<em>        }</em>

The next line initializes GCD to 1

       int gcd = 1;

The GCD is calculated using the following for loop

The GCD is the highest number that can divide both numbers

<em>        for(int i=1;i<=least;i++)</em>

<em>        {</em>

<em>            if(num1%i == 0 && num2%i == 0)</em>

<em>            {</em>

<em>                gcd = i;</em>

<em>            }</em>

<em>        }</em>

The following is printed if the calculated GCD is 1

       if(gcd == 1)

       {

           System.out.print("GCD is 1");

       }

Otherwise, the following is printed

       else

       {

           System.out.print("GCD is "+gcd);

       }

8 0
3 years ago
WOULD SOMEONE PLEASE ANSWER THIS IVE ASKED TWICE ALREADY!
Rainbow [258]
I think that’s right, hope it helps!:) brainliest??

7 0
3 years ago
Jason, Samantha, Ravi, Sheila, and Ankit are preparing for an upcoming marathon. Each day of the week, they run a certain number
kolbaska11 [484]

Answer:

C++ program explained below for the problem

Explanation:

// UpComingMarathon.cpp : Defines the entry point for the console application.

//header files

#include "stdafx.h" //optional

#include <iostream>

#include <cstring>

#include <fstream>

#include <iomanip>

using namespace std;

//declare the gobal array of type double

double average[5];

//declare the function prototypes

void getData(ifstream& inf, string n[], double runData[][8], int count);

void calculateAverage(double runData[][8], int count);

void print(string n[], double runData[][8], int count);

int main()

{

   string names[5];

   double runningData[5][8];

   ifstream inputfile("input.txt");

   if(inputfile)

   {

        //call the method getData

        getData(inputfile, names, runningData, 5);

   }

   else

   {

        //error message

        cout<<"Sorry! Unable to open the file."<<endl;

        system("pause");

        return 0;

   }

   //close the file

   inputfile.close();

   //call the method calculateAverage to compute the

   //average miliage of each runner

   calculateAverage(runningData, 5);

   //call display the names and their weekly run rate and their averages

   print(names, runningData, 5);

   system("pause");

   return 0;

}

//definition of method getData that reads the data from the file and

//stores the names into array n and run data into runData array

//simultaneously.

void getData(ifstream& inf, string n[], double runData[][8], int count)

{  

   while(!inf.eof())

   {

        for(int i=0;i<count; i++)

        {

            inf>>n[i];

            for(int j=0;j<7;j++)

            {

                inf>>runData[i][j];

            }

        }

   }

}

//definition of method calculateAverage that comptes the total first

//then stores the value of average into the average array

void calculateAverage(double runData[][8], int count)

{

   double total;

   for(int i=0;i<count;i++)

   {

        total=0;

        for(int j=0;j<7;j++)

        {

            total+=runData[i][j];

        }        

        average[i]=total/7;      

   }

}

//definition of method print that prints the output

//in a tabular format

void print(string n[], double runData[][8], int count)

{

   cout<<setfill('=')<<setw(80)<<"=";

   cout<<setfill(' ');

   cout<<endl;

   cout<<"Name"<<setw(6)<<"";

   for(int i=0;i<7;i++)

        cout<<setw(7)<<"Day "<<(i+1);

   cout<<setw(12)<<"Average"<<endl;

   cout<<setfill('=')<<setw(80)<<"=";

   cout<<setfill(' ')<<endl;

   for(int i=0;i<count;i++)

   {

        cout<<n[i]<<setw(8)<<fixed<<"";

        for(int j=0;j<7; j++)

        {

            cout<<setprecision(2)<<fixed<<runData[i][j]<<setw(3)<<"";

        }

        cout<<setw(8)<<average[i];

        cout<<endl;

   }

   cout<<setfill('=')<<setw(80)<<"=";

   cout<<endl;

}

5 0
3 years ago
Which key retains its uniqueness even after you remove some of the fields?
Natasha_Volkova [10]

Answer:

Primary key retains its uniqueness even after you remove some of the fields.

Explanation:

I am assuming that this question is related to database. Therefore, I am answering it according to database context.

In database, you can have multiple rows and columns. Each column shows a specific attribute while each row plots the data according to the attributes. However, there is the first column of each of main table that has unique set of values. It is called the Primary Key. Some key features of primary key are:

  • It always contains the unique value.
  • Its value cannot be null.
  • A table can have at max one primary key.
  • It can be the combination of multiple columns but it must be unique.

Therefore, the primary key has the ability to retain its uniqueness even after you remove some of the fields.

8 0
4 years ago
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