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4 years ago

Which statement is true regarding the "relationship merry-go-round"?

2 answers:

7 0

A common finding with couples who can’t connect or resolve their problems is that they reason out or feel that it’s the other individual who can’t connect, not them. It’s the other individual that has the problem and they remain to think "I’m right and you’re wrong." The answer is letter a. <span>In 40 percent of new weddings, one or both partners has been wedded no less than once before. Men are more probable to re-wed than women who've been wedded before.</span>

s344n2d4d5 [400]4 years ago

5 0

What was the correct answer?

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a person hears an echo from the top of a tower , 2.2 second after the sound is produced.how far away is the tower from the perso

bekas [8.4K]

Answer:

730.4 m

Explanation:

The sound waves travels with a uniform motion (=constant velocity), therefore we can calculate the distance it travels using the formula:

$d=vt$

where

d is the distance

v is the speed of the sound wave

t is the time taken

In this problem we have:

v = 332 m/s is the speed of sound in air

t = 2.2 s is the time elapsed

Therefore, the distance between the tower and the person is

$d=(332)(2.2)=730.4 m$

5 0

3 years ago

which of the laws of motion states to every action there is an equal but opposite reaction letter a Newton's first law see Newto

nataly862011 [7]

Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects.

5 0

3 years ago

Object A is moving due east, while object B is moving due north. They collide and stick together in a completely inelastic colli

Pie

Answer:

a) v = 3,843 m / s, b) 46.7º North- East

Explanation:

Moment is a vector quantity, so one of the best ways to solve this problem is to solve each component separately.

The system is formed by the two vehicles so that the moment is preserved during the crash

Direction to the East

initial instant. Before the crash

p₀ = mₐ vₐ₀

final insttne. After the crash

p_f = (mₐ + m_b) vₓ

p₀ = p_f

mₐ vₐ₀ = (mₐ + m_b) vₓ

vₓ = $\frac{m_a}{m_a + m_b} \ v_{ao}$

let's calculate

vₓ = $\frac{16.7}{16.7 + 29.3} \ 7.26$

vₓ = 2,636 m / s

direction north

initial p₀ = m_b v_{bo}

final p_f = (mₐ + m_b) v_y

p₀ = p_f

m_b v_{bo} = (mₐ + m_b) v_y

v_y = $\frac{m_b}{m_a+m_b} \ v_{bo}$

let's calculate

v_y = $\frac{29.3}{16.7 + 29.3} \ 4.39$

v_y = 2.796 m / s

the final speed of the two two vehicles is

v = (2,636 i ^ + 2,796 j ^) m / s

a) the magnitude of the velocity

let's use the Pythagorean theorem

v = $\sqrt{v_x^2 + v_y^2}$

v = $\sqrt{2.636^2 + 2.796^2}$

v = 3,843 m / s

b) let's use trigonometry to find the direction

tan θ = v_y / vₓ

θ = tan⁻¹ v_y / vₓ

θ = tan⁻¹ (2,796 / 2,636)

θ = 46.7º

This direction is 46.7º North East

7 0

3 years ago

Samuel applies a horizontal force of 35.0 N to a sleigh over a distance of 1.50 m along a level surface. Calculate the work done

Ronch [10]

Answer:

52.5 J

Explanation:

Work done (W) is the product of the force (F) applied on a body and the distance (s) moved in the direction of the force.

i.e W = F × s

It is a scalar quantity and measured in Joules (J).

Given that: F = 35.0 N and s = 1.50 m, then;

W = F × s

W = 35.0 × 1.5

= 52.5 J

Therefore, the work done on the sleigh by Samuel is 52.5 J.

5 0

3 years ago

Plz help >:

svlad2 [7]

Answer:

10m

Explanation:

The object distance and image distance is the same from the mirror. so the image is 5m behind the mirror.

5+5=10

5 0

3 years ago