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Lyrx [107]
3 years ago
8

joe's cell phone costs him $21 per month plus $3 for every 1GB of data downloaded. What is the limit to the number of GBs he can

download to stay within his monthly budget of $30.
Mathematics
2 answers:
Kruka [31]3 years ago
6 0
3GB’s you just add 21 to 3 and keep adding 3 until you reach 30

21+3=24 24+3=27 27+3=30
asambeis [7]3 years ago
4 0

joe can only use 3gb of data . bill is 21

21+9+30

1gb=3

3*9=9

3(3)+21=30

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Juli2301 [7.4K]

The given equation is,

\begin{gathered} x^2=0 \\ x=0 \end{gathered}

Thus, option (C) is the correct solution.

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blagie [28]

Answer:

Step-by-step explanation:

Start box

180 = 89+42+x

180-89-42=x

49 = x

2nd box

180 = 84+58+x

180-84-58=x

38 = x

3rd box

180=74+2x

180-74=2x

106/2 = x

53 = x

4th box

180=102+2x

180-102=2x

78/2 = x

39 = x

4th box

180 = 73+81 +x

180-73-81=x

26 = x

5th box

180=2*54+x

180 - 2*54 = x

72 = x

6th box

180=62-2x

180-62=2x

118=2x

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3 0
2 years ago
Use the given function and the given interval to complete parts a and b. f (x )f(x)equals=negative 2 x cubed plus 21 x squared m
Leya [2.2K]

Answer:

(A)The absolute maximum of f(x) is at x=5

Step-by-step explanation:

F(x)=−2x³+21x²−60x on [1,6]

Find the first derivative.

f'(x)=-6x²+42x-60

Set the first derivative equal to zero.

-6x²+42x-60=0

Solve to find the critical points.

x=2,5

Next, we use the endpoints and all critical points on the interval to test for any absolute extrema over the given interval.

x=1,2,5,6

This is done by evaluating the function at x=1,2,5,6.

F(1)=−2(1)³+21(1)²−60(1)=-41

F(2)=−2(2)³+21(2)²−60(2)=-52

F(5)=−2(5)³+21(5)²−60(5)=-25

F(6)=−2(6)³+21(6)²−60(6)=-36

The maximum will occur at the highest f(x) value and the minimum will occur at the lowest f(x) value.

Absolute Maximum: (5,-25)

Absolute Minimum: (2,-52)

The graph is attached.

The absolute minimum and maximum of f(x) are (2,-52) and (5,-25) respectively.

3 0
3 years ago
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