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Blababa [14]
3 years ago
10

A 50 gallon container is filled with 8 gallons of household cleaner. What fraction of the container is filled with household cle

aner?
Mathematics
1 answer:
Rudiy273 years ago
7 0
The fraction of the container that us filled with household cleaner is given by:
(amount of cleaner)/(total volume of the container )
=8/50
=4/25
answer: 4/25
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What percentage of 48 is 62?
Mila [183]

Answer:

129

Step-by-step explanation:

6 0
3 years ago
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Customers arrive at a service facility according to a Poisson process of rate λ customers/hour. Let X(t) be the number of custom
mash [69]

Answer:

Step-by-step explanation:

Given that:

X(t) = be the number of customers that have arrived up to time t.

W_1,W_2... = the successive arrival times of the customers.

(a)

Then; we can Determine the conditional mean E[W1|X(t)=2] as follows;

E(W_!|X(t)=2) = \int\limits^t_0 {X} ( \dfrac{d}{dx}P(X(s) \geq 1 |X(t) =2))

= 1- P (X(s) \leq 0|X(t) = 2) \\ \\ = 1 - \dfrac{P(X(s) \leq 0 , X(t) =2) }{P(X(t) =2)}

=  1 - \dfrac{P(X(s) \leq 0 , 1 \leq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}

=  1 - \dfrac{P(X(s) \leq 0 ,P((3 \eq X(t)) - X(s) \leq 5 ) }{P(X(t) = 2)}

Now P(X(s) \leq 0) = P(X(s) = 0)

(b)  We can Determine the conditional mean E[W3|X(t)=5] as follows;

E(W_1|X(t) =2 ) = \int\limits^t_0 X (\dfrac{d}{dx}P(X(s) \geq 3 |X(t) =5 )) \\ \\  = 1- P (X(s) \leq 2 | X (t) = 5 )  \\ \\ = 1 - \dfrac{P (X(s) \leq 2, X(t) = 5 }{P(X(t) = 5)} \\ \\ = 1 - \dfrac{P (X(s) \LEQ 2, 3 (t) - X(s) \leq 5 )}{P(X(t) = 2)}

Now; P (X(s) \leq 2 ) = P(X(s) = 0 ) + P(X(s) = 1) + P(X(s) = 2)

(c) Determine the conditional probability density function for W2, given that X(t)=5.

So ; the conditional probability density function of W_2 given that  X(t)=5 is:

f_{W_2|X(t)=5}}= (W_2|X(t) = 5) \\ \\ =\dfrac{d}{ds}P(W_2 \leq s | X(t) =5 )  \\ \\  = \dfrac{d}{ds}P(X(s) \geq 2 | X(t) = 5)

7 0
4 years ago
The functions g and h are given by g(x) = x + 1 and h(x) = x²
Delvig [45]

Answer:

x = - \frac{3}{2} , x = 2

Step-by-step explanation:

To find h(g(x)) substitute x = g(x) into h(x) , that is

h(g(x))

= h(x + 1)

= (x + 1)²

= x² + 2x + 1

For h(g(x)) = 3x² + x - 5 , then

3x² + x - 5 = x² + 2x + 1 ← subtract x² + 2x + 1 from both sides

2x² - x - 6 = 0 ← in standard form

(2x + 3)(x - 2) = 0 ← in factored form

Equate each factor to zero and solve for x

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = - \frac{3}{2}

x - 2 = 0 ⇒ x = 2

5 0
3 years ago
Which transformation shows that the two given circles are similar?
gregori [183]
Circle A -- center(2, 0), radius 8 Circle A' -- center(-1, 5), radius 3
3 0
4 years ago
Round 13 to the nearest 10.
mr Goodwill [35]

Round down to 10. 13 goes to 10.

3 0
3 years ago
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