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LenaWriter [7]
3 years ago
13

Include an explanation of how the surface area-to-volume ratio, diffusion rate, and time for substances to reach the center are

related. Support your explanation with data.
HELP PLZZ!!! 60 points!!!
Biology
1 answer:
Solnce55 [7]3 years ago
5 0

Answer:

Explanation: When the cell increases in size, the volume increases faster than the surface area, because volume is cubed where surface area is squared. When there is more volume and less surface area, diffusion takes longer and is less effective. ... this is actually why cells divide.

Explanation:

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If acetyl-CoA is labeled with 14C at its methyl group, how many rounds of the cycle are required before 14CO2 is released?
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Answer:

14 CO₂ will be released in the second turn of the cycle

Explanation:

<u>Complete question goes like this</u>, "<em>The CO2 produced in one round of the citric acid cycle does not originate in the acetyl carbons that entered that round. If acetyl-CoA is labeled with 14C at the carbonyl carbon, how many rounds of the cycle are required before 14CO2 is released?</em>"

<u>The answer to this is</u>;

  • The labeled Acetyl of Acetyl-CoA becomes the terminal carbon (C4) of succinyl-CoA (which becomes succinate that is a symmetrical four carbon diprotic dicarboxylic acid from alpha-ketoglutarate).
  • Succinate converts into fumarate. Fumarate converts into malate, and malate converts into oxaloacetate. Because succinate is symmetrical, the oxaloacetate can have the label at C1 or C4.
  • When these condense with acetyl-CoA to begin the second round of the cycle, both of these carbons are discharged as CO2 during the isocitrate dehydrogenase and alpha-ketoglutarate dehydrogenase reactions (formation of alpha-ketoglutarate and succinyl-CoA respectively).

Hence, 14 CO₂ will be released in the second turn of the cycle.

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