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Alex777 [14]
3 years ago
6

Which of the following is least accurately represented by the Venn diagram above?

Mathematics
2 answers:
Trava [24]3 years ago
8 0

Answer:

whats the answer

Step-by-step explanation:


Vaselesa [24]3 years ago
3 0
Can't see the diagram
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I’m plz help fast thanks <br><br><br><br> 16
nataly862011 [7]

Answer:

1/2 <3/4

Step-by-step explanation:

1/2   vs 3/4

We need a common denominator of 4

1/2*2/2   vs   3/4

2/4  vs 3/4

Since the denominators are the same, we compare the numerators

2 <3  so

2/4 < 3/4

1/2 <3/4

5 0
4 years ago
Find the length of the line segment inside the rectangular prism.
disa [49]

To find the length of the yellow segment, we have to use Pythagorean's Theorem. But first, we have to find the length of the black line at the bottom.

c^2=a^2+b^2

Where a = 4ft and b = 9ft.

\begin{gathered} c^2=4^2+9^2 \\ c^2=15+81 \\ c=\sqrt[]{96} \\ c\approx9.8 \end{gathered}

So, the length of the black segment is 9.8 feet.

Now, we find the yellow line length

c^2=a^2+b^2

Where a = 4 and b = 6.

\begin{gathered} c^2=4^2+6^2 \\ c^2=16+36 \\ c^2=52 \\ c=\sqrt[]{52} \\ c\approx7.2 \end{gathered}<h2>Therefore, the length of the yellow line is 7.2 feet.</h2>
8 0
1 year ago
Which correctly describes how the graph of the inequality 6y-3x&gt;9 is shaded
rewona [7]
We already know that it will be a dashed line because there is no equal sign in the problem.

6y - 3x > 9
6y > 3x + 9
y > 3/6x + 9/6
y > 1/2x + 3/2

<span>And greater then means shaded above the line.

I hope this helped! :)
Please mark as brainliest!</span>
7 0
3 years ago
Solve for all values of x by factoring.<br> x^2 + 4x – 30 = -3x
vichka [17]

Answer:

{x}^{2}  + 4x - 30 =  - 3x \\{x}^{2}  + 7x - 30 = 0 \\  {x}^{2}  - 3x + 10x - 30 = 0 \\ x(x - 3) + 10(x - 3) = 0 \\ (x - 3)(x + 10) = 0 \\  \boxed{x = 3} \\  \boxed{x =  - 10}

<h3><em><u>x=3 or x=-10</u></em> is the right answer.</h3>

7 0
3 years ago
GEOMETRY 10TH GRADE NEED HELP ASAP
Maru [420]

\boxed{(6, -3)}

Step-by-step explanation:

Given the ratio 5:3

and Points A and B where A is located at (-6, 3), and B is located at (26, -13).

Let point A be (x_{1}, y_{1}), and let point B be (x_{2}, y_{2}).

(-6, 3) → (x_{1}, y_{1}).

(26, -13) → (x_{2}, y_{2}).

Let 5 be n, and 3 be m.

5:3 → n:m

(\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}).

To solve, just substitute these variables into the expressions of these coordinates to get the answer.

(\frac{nx_{1} + mx_{2}}{n+m}, \frac{ny_{1} + my_{2}}{n + m}) →

(\frac{(5)x_{1} + (3)x_{2}}{(5)+(3)}, \frac{(5)y_{1} + (3)y_{2}}{(5) + (3)}) →

(\frac{(5)(-6)+ (3)(26)}{(5)+(3)}, \frac{(5)(3)+ (3)(-13)}{(5) + (3)}) →

(\frac{-30 + 78}{8}, \frac{15+ -39}{8}) →

(\frac{78 – 30}{8}, \frac{15 – 39}{8}) →

(\frac{48}{8}, \frac{-24}{8})

→

(\frac{6}{1}, \frac{-3}{1})

→

(6, -3).

Thus the coordinates of B are:

\boxed{(6, -3)}

4 0
3 years ago
Read 2 more answers
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