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3 years ago

2+2×2 (169×12)+387 255+40÷2+372

Mathematics

2 answers:

slava [35]3 years ago

7 0

2 + 2 x 2
= 2+4
= 6
( 169 x 12 ) + 387
= 2028 + 387
= 2415 *
255 + 40 / 2 + 372
=255+ 20 + 372
= 647

egoroff_w [7]3 years ago

4 0

For the first equation lets first multiply 2 * 2 which is 4 and add 4 + 2 which is 6 and that would be your answer.

For the second equation we want to first multiply 169 * 12 and we get 2028 so now we add 2028 + 387 and we get our answer which is 2415.

For the last equation we want to divide 40 and 2 so we get 20, and then we add 255 + 20 + 372 and we get our answer which is 647.

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Write a fraction equal to 1 and that has a denominator of 5.

photoshop1234 [79]

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3 years ago

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Answer:

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Step-by-step explanation:

Let's subtract:

$( - 8 {x}^{2} - 8) - (x - 4)$

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2 years ago

30 POINTS FOR THE GENUIS WHO CAN ANSWER THIS!!

bearhunter [10]

Answer:

Answers are below in bold

Step-by-step explanation:

1) A = 1/2bh Use this equation to find the area of each triangular base

A = 1/2(8)(6) Multiply

A = 1/2(48) Multiply

A = 12cm² Area of each triangular base

2) A = L x W Use this equation to find the area of the bottom rectangular face

A = 20 x 8 Multiply

A = 160 cm² Area of the bottom rectangular face

3) A = L x W Use this equation to find the area of the back rectangular face

A = 20 x 6 Multiply

A = 120 cm² Area of the back rectangular face

4) A = L x W Use this equation to find the area of the sloped rectangular face

A = 20 x 10 Multiply

A = 200 cm² Area of the sloped rectangular face

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3 years ago

In a NiCd battery, a fully charged cell is composed of Nickelic Hydroxide. Nickel is an element that has multiple oxidation stat

Westkost [7]

Answer:

P(cell has at least one of the positive nickel-charged options) = 0.83.

P(a cell is not composed of a positive nickel charge greater than +3) = 0.85.

Step-by-step explanation:

It is given that the Nickel Charge Proportions found in the battery are:

0 ==> 0.17

+2 ==> 0.35

+3 ==> 0.33

+4 ==> 0.15.

The numbers associated to the charge are actually the probabilities of the charges because nickel is an element that has multiple oxidation states that is usually found in the above mentioned states.

a) P(cell has at least one of the positive nickel-charged options) = P(a cell has +2 nickel-charged options) + P(a cell has +3 nickel-charged options) + P(a cell has +4 nickel-charged options) = 0.35 + 0.33 + 0.15 = 0.83.

Or:

P(a cell has at least one of the positive nickel-charged options) = 1 - P(a cell has 0 nickel-charged options) = 1 - 0.17 = 0.83.

b) P(a cell is not composed of a positive nickel charge greater than +3) = 1 - P(a cell is composed of a positive nickel charge greater than +3)

= 1 - P(a cell has +4 nickel-charged options) '.' because +4 is only positive nickel charge greater than +3

= 1 - 0.15

= 0.85

To summarize:

P(cell has at least one of the positive nickel-charged options) = 0.83!!!

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3 years ago

42:28

gogolik [260]

Answer:

The statements about arcs and angles that are true in the figure are;

1) ∠EFD ≅ ∠EGD

2) $\overline{ED}\cong \overline{FD}$

3) mFD = 120°

Step-by-step explanation:

1) ∠ECD + ∠CEG + ∠CDG + ∠GDE = 360° (Sum of interior angle of a quadrilateral)

∠CEG = ∠CDG = 90° (Given)

∠GDE = 60° (Given)

∴ ∠ECD = 360° - (∠CEG + ∠CDG + ∠GDE)

∠ECD = 360° - (90° + 90° + 60°) = 120°

∠ECD = 2 × ∠EFD (Angle subtended is twice the angle subtended at the circumference)

120° = 2 × ∠EFD

∠EFD = 120°/2 = 60°

∠EFD ≅ ∠EGD

∠ECD = 120°

∠EGD = 60°

∴∠EGD ≠ ∠ECD

2) Given that arc mEF ≅ arc mFD

Therefore, ΔECF and ΔDCF are isosceles triangles having two sides (radii EC and CF in ΔECF and radii EF and CD in ΔDCF

∠ECF = mEF = mFD = ∠DCF (Given)

∴ ΔECF ≅ ΔDCF (Side Angle Side, SAS, rule of congruency)

$\\ \overline{EF}\cong \overline{FD}$ (Corresponding Parts of Congruent Triangles are Congruent, CPCTC)

∠FED ≅ ∠FDE (base angles of isosceles triangle)

∠FED + ∠FDE + ∠EFD = 180° (sum of interior angles of a triangle)

∠FED + ∠FDE = 180° - ∠EFD = 180° - 60° = 120°

∠FED + ∠FDE = 120° = ∠FED + ∠FED (substitution)

2 × ∠FED = 120°

∠FED = 120°/2 = 60° = ∠FDE

∴ ∠FED = ∠FDE = ∠EFD = 60°

ΔEFD is an equilateral triangle as all interior angles are equal

$\\ \overline{EF}\cong \overline{FD}\cong \overline{ED}$ (definition of equilateral triangle)

$\overline{ED}\cong \overline{FD}$

3) Having that ∠EFD = 60° and ∠CFE = ∠CFD (CPCTC)

Where, ∠EFD = ∠CFE + ∠CFD (Angle addition)

60° = ∠CFE + ∠CFD = ∠CFE + ∠CFE (substitution)

60° = 2 × ∠CFE

∠CFE =60°/2 = 30° = ∠CFD

$\overline{CF}\cong \overline{CD}$ (radii of the same circle)

ΔFCD is an isosceles triangle (definition)

∠CFD ≅ ∠CDF (base angles of isosceles ΔFCD)

∠CFD + ∠CDF + ∠DCF = 180°

∠DCF = 180° - (∠CFD + ∠CDF) = 180° - (30° + 30°) = 120°

mFD = ∠DCF (definition)

mFD = 120°.

5 0

3 years ago