13*18
x*y =234
x+y=31
we know the 2 # have to be double digits and both between 10-20
find 2 values that * to a number that ends in 4. Those are the ones value
1*4 11 and 14
2*2 12 and 12
3*8 13 and 18
only 13 and 18 add up to 31 and multiply to 234
Answer: 
<u>Step-by-step explanation:</u>

Option A:

Solution:
Given expression
.
To find the product of the above expression:

First multiply first two factors with each term.

Using exponent rule: 

Now multiply these two factors with each term.


Using exponent rule:



Hence option A is the correct answer.
Answer:
- <u>Each digit has a value ten times the value of the digit to its right.</u>
Explanation:
The given number is 9,999,999.
Each digit has a value according to its place.
The right most 9 is in the place of the ones and its value is 9 × 10⁰ = 9 × 1 = 9.
The second 9 from the right is in the place of the tens and its value is 9 × 10 = 90.
The third 9 from the right end is in the place of the hundreds and its value is 9 × 100 = 900.
The next 9 is in the place of the thousands, so its value is 9,000.
So, each 9 has a value ten times the 9 to its right.
A = 1 b = -10 c = -20
Using the quadratic formula,
x = [--10 +-sqr root (100 -4*1*-20)] / 2*1
x = [10 +- sqr root (180)] / 2
x = 10/2 +- (sqr root (180) / 2)
x = 5 +- (3 * sqr root (20) / 2)
x = 5 +- (6 * sqr root (5) / 2)
x = 5 +- 3 * sqr root (5)
So the answer is #3