Answer: 1)c. -6
2)B.4
Step-by-step explanation:
1)It would be: -4(3r - 2) - 2(r+1)
= -12r + 8 - 2r - 2
= -14r + 6
2)When we have an equation like 1x, and x = 2, then that means that we are multiplying by x or 1 * x. So, a = 2 and b = 3, we have to multiply 3 & 2 by 2, and 2 by b. (3 * a(2) ==> 6) ~~ (2 * 2 ==> 4) ~~ (2 * 3 ==> 6) Now, we have 6 - 6 + 4. Evalutate. (6 - 6 ==> 0) ~~ (0 + 4 ==> 4) 4 is the final
Answer:
It's the only thing we can do right now. Going back is a recipe for disaster.
Step-by-step explanation:
This problem involves the use of a kinematic equation since it involves the motion of an object. The equation for the height of the object is given as:
s = -<span>16*t^2+v_o*t
Also, the initial velocity, v_o, was also said to be equal to 128 ft/s.
For the first question, </span><span>the time(s) that the projectile will reach a height of 240 ft when v_o is 128 feet per second, can be solved using the given equation and the quadratic formula. The resulting quadratic equation is then </span>-16*t^2 + 128*t -240 =0, where a =16, b =128, and c =-240. The quadratic formula is equal to [-b <span>± sqrt(b^2 -4ac)]/2a. This gives two answers t = 3 seconds and t = 5 seconds. This might be because the projectile has a parabolic path, thus, it reaches the height of 240 ft, before and after it reaches a peak.
For the second question, the time it takes for the projectile to reach the ground is obtained by setting the distance, s, equal to zero. In this case, t = 8 seconds.</span>
4 goes into 11 twice
thats 2 for the whole number and for the fraction you have 3/4 left over
so 11/4=2 3/4
To figure this out, you'd use the a^2+b^2=c^2 formula. Since you have your two sides, you want to find the value for c. So, you'd plug in two for a and b.
2^2+2^2=c^2
4+4=c^2
Add up the two fours to get 8 and square root it, and you get 2.828427124...
, 22.7