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EleoNora [17]
3 years ago
14

Which list shows the numbers in order from least to greatest?

Mathematics
1 answer:
nata0808 [166]3 years ago
7 0

Answer: second one (B) - 2.045, 2.43, 259


Step-by-step explanation: 2.045 is the lowest value due to the 0 in the hundredths place. 2.43 has a lower value than 259, it being a decimal.


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Hello everyone can you answer this for me? What is A in the equation attached? Please and thank you.
lapo4ka [179]

Answer:

a = 6

Step-by-step explanation:

Hello!

Solve:

  • 4(3a - 4) = 56
  • 3a - 4 = 14          (factoring out 4)
  • 3a = 18               (adding 4 to both sides)
  • a = 6                   (dividing by 3)

Another way:

  • 4(3a - 4) = 56
  • 12a - 16 = 56        (distributive property)
  • 12a = 72               (moving like terms)
  • a = 6                    (dividing by 12)

Distributive Property of Multiplication:

The process of distributing the outside factor to the terms in the parenthesis.

Example:

4(3a - 4)\\\\4(3a) - 4(4)\\\\12a - 16

7 0
3 years ago
Read 2 more answers
Solve for n: c= 6n−5g /11t
qwelly [4]

Answer: \frac{11tc+5g}{66t}=n

Step-by-step explanation:

You have the equation c=6n-\frac{5g}{11t}.

Then, to solve for the variable n from the equation you need:

Make the subtraction of the right side of the equation:

(As the denominators are 1 and 11t, the least common denominator is 11t)

c=\frac{(6n)(11t)-5g}{11t}\\\\c=\frac{66nt-5g}{11t}

Multiply  11t to both sides:

(11t)c=(\frac{66nt-5g}{11t})(11t)\\\\11tc=66nt-5g

Add 5g to both sides:

11tc+5g=66nt-5g+5g\\\\11tc+5g=66nt

And finally divide both sides by 66t:

\frac{11tc+5g}{66t}=\frac{66nt}{66t}\\\\\frac{11tc+5g}{66t}=n

3 0
3 years ago
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ra1l [238]
The answer would be ay-xb
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Jeanette can walk 1 km in 11 minutes. At the same rate, how far can she walk in 55 minutes?
gladu [14]
11 minutes = 1 km

11 x 5 = 55 minutes
1 x 5 = 5 km.

She can walk 5 km in 55 minutes.
3 0
3 years ago
Read 2 more answers
Help me plz apperciat it
nata0808 [166]

Answer:

24

Step-by-step explanation:

I have had this question before I know the answer

4 0
3 years ago
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