Answer:
2
Step-by-step explanation:
-6+10x=x+12
Add 6 to both sides:
10x=x+18
Subtract x from both sides:
9x=18
Divide both sides by 9:
x=2
Hope this helps!
The slope of AC is -0.4
Proof:
In triangles ABC and DBE,
∠DBE is common to both triangles.
AB = 2DB (D is the midpoint of the interval AB)
Also, BC = 2BE (E is the midpoint of the interval BC)
Thus triangles ABC and DBE are similar in the ratio 2:1
Since, they are similar, ∠BDE must equal ∠BAC (corresponding angles in similar triangles)
If ∠BDE = ∠BAC, DE must be parallel to AC (corresponding angles are equal along parallel lines)
Thus, the slope of AC = the slope of DE
Thus, the slope of AC is -0.4
The shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet
<h3>What dimensions would guarantee that the garden has the greatest possible area?</h3>
The given parameter is
Perimeter, P = 520 feet
Represent the shorter side with x and the longer side with y
One side of the garden is bordered by a river:
So the perimeter is:
P = 2x + y
Substitute P = 520
2x + y = 520
Make y the subject
y = 520 - 2x
The area is
A = xy
Substitute y = 520 - 2x in A = xy
A = x(520 - 2x)
Expand
A = 520x - 2x^2
Differentiate
A' = 520 - 4x
Set to 0
520 - 4x = 0
Rewrite as:
4x= 520
Divide by 4
x= 130
Substitute x= 130 in y = 520 - 2x
y = 520 - 2 *130
Evaluate
y = 260
The area is then calculated as:
A = xy
This gives
A = 130 * 260
Evaluate
A = 33800
Hence, the shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet
Read more about area at:
brainly.com/question/24487155
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Answer:
r=9/2 or 4.5
Step-by-step explanation:
First of all our goal is to get R by itself
by cross multiplying we get,
(r+3)*3=5r
by distributive property we get
3r+9=5r
substracting 3r from both sides we get
9=2r
by dividing by 2 in both sides we get
r=9/2 or 4.5
Answer:
1. 
( in this inequality, the time can be less than or equal to 45, but no more than 45)
2. 
(Mario's height is more than 60.)
3. 
(More than 8000 fans attended.)
