Write an equation in standard form. Y+2=2/3(x+4)
1 answer:
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Answer:
Critical points are 1 and -1
Maximum at x=1
Minimum at x=-1
Step-by-step explanation:
We are given that a function
on (
)
We have to find the critical points of the function.
To find the critical point we will differentiate function w.r.t x and then substitute f'(x)=0
Therefore, the critical points of the given function are 1 and -1.
When we goes from 0 to 2 then the sign of derivative change from positive to negative .Therefore, function has local maximum at x=1.
When we goes form -2 to 0 then the sign of derivative change from negative to positive .Hence , function has local minimum at x=-1
Hence, critical points are local maximum and local minimum .