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stiv31 [10]
3 years ago
15

You have been found at fault in a crash where someone was injured and was transported to a medical treatment facility. By law yo

u must
A: Attend a Traffic Collision Avoidance Course.
B: Retake your Class E road rules test.
C: Pay a $150 service fee to the Medical Emergency Fund.
Computers and Technology
2 answers:
finlep [7]3 years ago
4 0

Answer:

If you are found at fault in a collision where anyone is injured and transported to a medical treatment facility or it is your second collision in a  two year period, you will be required by law to attend a traffic collision avoidance course.

The answer is A

Explanation:

romanna [79]3 years ago
3 0

Answer:

A: Attend a Traffic Collision Avoidance Course.

Explanation:

If you are found guilty in a crash where someone was injured and was transported to a medical treatment facility, the law states that you have to take a Traffic Collision Avoidance Course. This is a course in which people learn about driving safety and regulations like speed limits to avoid this type of situations to repeat.

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In 25 words or fewer, identify what calendar feature the recurring task function copies.
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4 years ago
How can you encrypt and decrypt a message in cryptography
ser-zykov [4K]
There are two main types of encryption - <span>symmetric and asymmetric. 

Using symmetric encryption, you use a single secret key that is used to both encrypt and decrypt the data. This form of encryption has been used way before computers! Without this key it is very hard to decrypt a message. However, the issue with this is that if you want to send an encrypted message, you also have to send a key to them, and </span>if your somebody unintended intercepts the key, they can read the message.

What's the solution? Asymmetric cryptography or public key encryption. Asymmetric cryptography uses encryption that splits the key into two smaller keys. One of the keys is public and one is kept private. A good metaphor for understanding this is the public key is the lock, and the private key is the key. You can encrypt a message to send to somebody with their public key, locking it, which they can then decrypt, unlock, with their private key. And vice versa. So with this kind of encryption it's very difficult to decrypt a message for anybody but the owner as it's much harder to steal when it doesn't need to leave their computer, but easy to encrypt messages to send to them

5 0
3 years ago
Consider the following code: x = int(input("Input an integer: ")) if (x &gt;= 0): print("Yay!") else: print("Boo!") It outputs "
Fed [463]
<h2>You have to apply the given condition in if loop.</h2>

Explanation:

if((x>=0) && (x%2==0))  

print("Yay!")

else

print("Boo!")

if((x>=0) && (x%2==0))  this statement is enough to check given expectation. the value of x is positive that is checked using  x>=0 and also the positive integer should be an even number is checked using the condition (x%2==0). The "&&" operator is used to check whether both the condition is true. So if the value of "x" is positive and even, "Yah!" will be printed. Otherwise "Boo!" will be printed.

All the other choice goes invalid becoz (x%2==1) will be true only if the number is an odd number.

7 0
3 years ago
Write a program that asks the user for two file names. The first file will be opened for input and the second file will be opene
Wewaii [24]

Answer:

#include <iostream>

#include <fstream>

#include <string>

using namespace std;

int main()

{

//First we declare string variables to store file names for input and output

   string inputName;

   string outputName;

   string sentence;

// Then declare char variable to get current char

   char ch;

//The following section will prompt theuser to enter the file names and read

   cout << "Enter input file name:\n";

   cin >> inputName;

   cout << "Enter output file name:\n";

   cin >> outputName;

//ignore newline character left inside keyboard buffer

   cin.ignore();

//Next we define the input and output files to be opened

   ifstream inputFile(inputName);

   ofstream outputFile(outputName);

   if(!inputFile && !outputFile){

       cout << "Error while opening the files!\n";

       cout << "Please try again!\n";

       //end program immediately

       return 0;

   }

//Using this loop to get lines one by one, delimited by '.'

   while(getline(inputFile, sentence, '.')){

       //bool variable to store if we have already

       //printed capital first letter

       bool alreadyCapitalized = false;

       //Using of for loop on all characters of sentence

       for(int counter = 0; counter < sentence.length(); counter++){

           //if not alphabetical character,

           //so whitespace or newline, print as is

           if(!isalpha(sentence[counter]))

               outputFile << sentence[counter];

       //Condition statement for if it is alphabetical and no capitalization has been done, print it as uppercase

           if(!alreadyCapitalized && isalpha(sentence[counter])){

               outputFile << (char)toupper(sentence[counter]);

               alreadyCapitalized = true;

           }

           //otherwise print this condition as lowercase

           else if(alreadyCapitalized)

               outputFile << (char)tolower(sentence[counter]);

       }

       //Printing of the output sentence with period in the end

       outputFile << ".";

   }

   //Closing the files

   inputFile.close();

   outputFile.close();

   return 0;

}

5 0
3 years ago
Please answer this question​
Vanyuwa [196]

Explanation:

A. Encryption. (B. Printer

6 0
3 years ago
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