Answer:
The phenotypic variance= 2113
The eenvironmenal variance= 644
The genetic variance= 1469
The broad-sense heritability = 0.695
Explanation:
To determine the phenotypic variance, we need to know the calculate the environmental variance and the genetic variance first;
because Phenotypic variance = V(p) such that;
V(p) = V(e) + V(g)
where V(e) = environmental variance and V(g) = genetic variance
Therefore, Environmental variance can be defined as a portion of phenotypic variance due to differences in the environments to which the individuals in a population have been exposed. The total amount of variance observed is dependent on the genetic component, determined by the variation that is inherited.
This implies that V(e)= initial variance which was there in the parents ( i.e Variance of inbred line 1 = 311 and Variance of inbred line 2 = 333 )
V(e) = (311 + 333) = 644
Genetic Variance simply refer to the variance that occurs or preferrably , that is observed after inbreeding (i.e Variance of F1 = 316 and Variance of F2 = 1153)
V(g) = (316 + 1153) = 1469
Now, back to phenotypic variance = V(e) + V(g)
substituting the parameters we have; 1469 + 644 = 2113
Broad-sense heritability can be calculated as the ratio of total genetic variance to total phenotypic variance.
= V(g)/ V(p)
= 1469/ 2113
= 0.695
