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lapo4ka [179]
2 years ago
9

The population that you're interested in has a mean of 60 and a standard deviation of 72 Step 2 of 2: If you calculate a(n) 93.1

2 % Confidence Interval on the Mean, what will your Margin of Error be? (Round to 2 decimal places.)
Mathematics
1 answer:
aivan3 [116]2 years ago
5 0

Answer:

Z = 8.41

Step-by-step explanation:

Given that standard deviation = 72

Mean = 60

Z = marginal error

Z = 72/√60

Z = 72/7.746

Z = (9.036)(0.9312)

Z = 8.41

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