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nikitadnepr [17]
3 years ago
12

All of the following are examples of quantitative data EXCEPT ________. All of the following are examples of quantitative data E

XCEPT ________. the cholesterol levels of the students in a class the exam scores for the students in a class the gender of the students in a class the number of siblings that students have the amount of sleep normally gotten by the students in a class
Mathematics
1 answer:
solniwko [45]3 years ago
3 0

Answer:

The gender of the students in a class

Step-by-step explanation:

Quantitative data is the data which can be counted or measured and expressed in terms of numbers with certain units of measurements with it.

Cholesterol level can be measured hence its quantitative data.

Exams scores of students can be counted and recorded in terms of numbers, hence this is quantitative data.

Gender of students cannot be measured or counted. This is a characteristic and ix expressed in words. Hence, this is not a quantitative data. Such a data is known as qualitative data

Number of siblings can be counted, hence this is quantitative data

Amount of sleep can be measured, hence this is quantitative data.

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Find cot and cos <br> If sec = -3 and sin 0 &gt; 0
Natali5045456 [20]

Answer:

Second answer

Step-by-step explanation:

We are given \displaystyle \large{\sec \theta = -3} and \displaystyle \large{\sin \theta > 0}. What we have to find are \displaystyle \large{\cot \theta} and \displaystyle \large{\cos \theta}.

First, convert \displaystyle \large{\sec \theta} to \displaystyle \large{\frac{1}{\cos \theta}} via trigonometric identity. That gives us a new equation in form of \displaystyle \large{\cos \theta}:

\displaystyle \large{\frac{1}{\cos \theta} = -3}

Multiply \displaystyle \large{\cos \theta} both sides to get rid of the denominator.

\displaystyle \large{\frac{1}{\cos \theta} \cdot \cos \theta = -3 \cos \theta}\\\displaystyle \large{1=-3 \cos \theta}

Then divide both sides by -3 to get \displaystyle \large{\cos \theta}.

Hence, \displaystyle \large{\boxed{\cos \theta = - \frac{1}{3}}}

__________________________________________________________

Next, to find \displaystyle \large{\cot \theta}, convert it to \displaystyle \large{\frac{1}{\tan \theta}} via trigonometric identity. Then we have to convert \displaystyle \large{\tan \theta} to \displaystyle \large{\frac{\sin \theta}{\cos \theta}} via another trigonometric identity. That gives us:

\displaystyle \large{\frac{1}{\frac{\sin \theta}{\cos \theta}}}\\\displaystyle \large{\frac{\cos \theta}{\sin \theta}

It seems that we do not know what \displaystyle \large{\sin \theta} is but we can find it by using the identity \displaystyle \large{\sin \theta = \sqrt{1-\cos ^2 \theta}}  for \displaystyle \large{\sin \theta > 0}.

From \displaystyle \large{\cos \theta = -\frac{1}{3}} then \displaystyle \large{\cos ^2 \theta = \frac{1}{9}}.

Therefore:

\displaystyle \large{\sin \theta=\sqrt{1-\frac{1}{9}}}\\\displaystyle \large{\sin \theta = \sqrt{\frac{9}{9}-\frac{1}{9}}}\\\displaystyle \large{\sin \theta = \sqrt{\frac{8}{9}}}

Then use the surd property to evaluate the square root.

Hence, \displaystyle \large{\boxed{\sin \theta=\frac{2\sqrt{2}}{3}}}

Now that we know what \displaystyle \large{\sin \theta} is. We can evaluate \displaystyle \large{\frac{\cos \theta}{\sin \theta}} which is another form or identity of \displaystyle \large{\cot \theta}.

From the boxed values of \displaystyle \large{\cos \theta} and \displaystyle \large{\sin \theta}:-

\displaystyle \large{\cot \theta = \frac{\cos \theta}{\sin \theta}}\\\displaystyle \large{\cot \theta = \frac{-\frac{1}{3}}{\frac{2\sqrt{2}}{3}}}\\\displaystyle \large{\cot \theta=-\frac{1}{3} \cdot \frac{3}{2\sqrt{2}}}\\\displaystyle \large{\cot \theta=-\frac{1}{2\sqrt{2}}

Then rationalize the value by multiplying both numerator and denominator with the denominator.

\displaystyle \large{\cot \theta = -\frac{1 \cdot 2\sqrt{2}}{2\sqrt{2} \cdot 2\sqrt{2}}}\\\displaystyle \large{\cot \theta = -\frac{2\sqrt{2}}{8}}\\\displaystyle \large{\cot \theta = -\frac{\sqrt{2}}{4}}

Hence, \displaystyle \large{\boxed{\cot \theta = -\frac{\sqrt{2}}{4}}}

Therefore, the second choice is the answer.

__________________________________________________________

Summary

  • Trigonometric Identity

\displaystyle \large{\sec \theta = \frac{1}{\cos \theta}}\\ \displaystyle \large{\cot \theta = \frac{1}{\tan \theta} = \frac{\cos \theta}{\sin \theta}}\\ \displaystyle \large{\sin \theta = \sqrt{1-\cos ^2 \theta} \ \ \ (\sin \theta > 0)}\\ \displaystyle \large{\tan \theta = \frac{\sin \theta}{\cos \theta}}

  • Surd Property

\displaystyle \large{\sqrt{\frac{x}{y}} = \frac{\sqrt{x}}{\sqrt{y}}}

Let me know in the comment if you have any questions regarding this question or for clarification! Hope this helps as well.

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