All categories

3 years ago

I need help answering this!

Mathematics

2 answers:

Paladinen [302]3 years ago

7 0

Answer:

360 (I thinks)

Step-by-step explanation:

listen if I type out how i got the answer it could take me a loooooong time.

MArishka [77]3 years ago

3 0

The answer should be 360

You might be interested in

Anyone can help me please?

mrs_skeptik [129]

Answer:

40% is what i think it is

6 0

3 years ago

Josephine wrote the number 1-100 and placed them in a bag. If she selects a number without looking, what is the probability that

nirvana33 [79]

22% since 100-78 is 22 so that is the percentage of numbers between 78 and 100

6 0

4 years ago

What is the value of f(7)

Lelu [443]

Answer:

7f

Step-by-step explanation:

You move 7 to the left of f.

This makes the exact value of f(7), 7f.

8 0

3 years ago

Consider the given function.

Natali5045456 [20]

Answer:

Step-by-step explanation:

f(x) = x^2 -14x -72

0=x^2 - 14x-72

0=x^2 - 18x+4x-72

0=x(x-18)+4(x-18)

0=(x-18)(x+4)

x-18=0 or x+4=0

x1=18 or x2=-4

asis of symmetry: x=(x1+x2)/2

x=(18+(-4))/2

x=14/2

x=7

3 0

3 years ago

A doctor released the results of clinical trials for a vaccine to prevent a particular disease. In these clinical trials, 200,0

CaHeK987 [17]

Answer:

1) No, there is not enough evidence to support the claim that the vaccine was effective (P-value=0.104) .

The null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

being the subindex 1 for the experimental group and subindex 2 for the control group.

2) Test statistic z=-1.26

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the vaccine was effective.

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2< 0$

The significance level is 0.01.

The sample 1 (experimental group), of size n1=100000 has a proportion of p1=0.0002.

$p_1=X_1/n_1=21/100000=0.0002$

The sample 2 (control group), of size n2=100000 has a proportion of p2=0.0003.

$p_2=X_2/n_2=30/100000=0.0003$

The difference between proportions is (p1-p2)=-0.0001.

$p_d=p_1-p_2=0.0002-0.0003=-0.0001$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{21+30}{100000+100000}=\dfrac{51}{200000}=0.00026$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.00026*0.99974}{100000}+\dfrac{0.00026*0.99974}{100000}}\\\\\\s_{p1-p2}=\sqrt{0+0.0000000025}=\sqrt{0.0000000051}=0.000071$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{-0.00009-0}{0.000071}=\dfrac{-0.00009}{0.000071}=-1.26$

This test is a left-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=P(z$

As the P-value (0.104) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the vaccine was effective.

6 0

3 years ago