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Ratling [72]
3 years ago
8

The estimated probability of a bowler getting a strike during a particular frame is 63%. If several simulations of the bowler bo

wling two frames were performed, in what percentage of the simulations would the bowler be most likely to get a strike in each of the two frames?
Mathematics
1 answer:
Vilka [71]3 years ago
3 0

Answer: Our required probability is 39.69%.

Step-by-step explanation:

Since we have given that

Probability of a bowler getting a strike during a particular frame = 63%

Number of frames are performed = 2

We need to find the probability that the bowler would be most likely to get a strike in each of the two frames.

So, it becomes,

\dfrac{63}{100}\times \dfrac{63}{100}=(0.63)^2\\\\=0.3969\\\\=39.69\%

Hence, Our required probability is 39.69%.

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krek1111 [17]
Let the numbers be x and y.  Then xy = -30 and  x+y = -3.

Solve xy = -30 for y:    y = -30/x

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Multiply all 3 terms by x:  x^2 - 30 = -3x, so   x^2 + 3x - 10 = 0

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kipiarov [429]

Answer:

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Step-by-step explanation:

Since we are dealing with below sea level our initial starting point and max level will both be negative values, while our descending rate will also be negative because we are going down. Using the values provided we can create the following inequality...

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(4x^3y^-5)^4

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