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Ratling [72]
3 years ago
8

The estimated probability of a bowler getting a strike during a particular frame is 63%. If several simulations of the bowler bo

wling two frames were performed, in what percentage of the simulations would the bowler be most likely to get a strike in each of the two frames?
Mathematics
1 answer:
Vilka [71]3 years ago
3 0

Answer: Our required probability is 39.69%.

Step-by-step explanation:

Since we have given that

Probability of a bowler getting a strike during a particular frame = 63%

Number of frames are performed = 2

We need to find the probability that the bowler would be most likely to get a strike in each of the two frames.

So, it becomes,

\dfrac{63}{100}\times \dfrac{63}{100}=(0.63)^2\\\\=0.3969\\\\=39.69\%

Hence, Our required probability is 39.69%.

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I need help so someone plz give me the steps and answer and graph it so i can understand how to solve these types of problems ag
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y + 6 = 4/5x + (3(4))/5

y + 6 = 4/5x + (12)/5
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y = 4/5x - 3.6 ( y = mx + b formula)

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y = 0.8x - 3.6

x = 1
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x = 2
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x = 3
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8 0
3 years ago
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3 years ago
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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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[Correct Question]

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