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Ratling [72]
3 years ago
15

Write a polynomial function $f$ of least degree that has rational coefficients, a leading coefficient of 1, and the given zeros.

Write the function in standard form -5,-1,2
Mathematics
1 answer:
olganol [36]3 years ago
4 0

Answer:

f(x) = x^{3} + 4x^{2} -7x^{} -10^{}

Step-by-step explanation:

The zeros of the polynomial function are given us as -5,-1,2

If the zeros of a polynomial function are α,β,ω, the polynomial function can be obtained using the expression below:

f(x) = (x - α)(x - β)(x - ω)

where α = -5, β = -1, and ω = 2

f(x)=(x-(-5) )(x -(-1))(x - 2) = (x+5)(x+1)(x-2)\\\\f(x)=(x+5)(x^{2} -2x + x -2) = (x+5)(x^{2}  -x-2)\\\\f(x)=x(x^{2}  -x-2)+5(x^{2}  -x-2)\\\\f(x)= x^{3} - x^{2} -2x + 5x^{2} - 5x - 10\\\\f(x)= x^{3} + 4x^{2} -7x - 10

<em>NB: To arrive at the answer, expand the brackets and after expansion, collect like terms to obtain the final answer</em>

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Read 2 more answers
-y^2+x^3-4x^3-6y^2+5-2-x^3
Alex

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{\texttt{{Hello}}}

\gray{\boxed{{\textsf{trouble}}}}

-y  ^ { 2  }  +x  ^ { 3  }  -4x  ^ { 3  }  -6y  ^ { 2  }  +5-2-x  ^ { 3  } \\

\green{\boxed{{\textsf{Development}}}}

-y  ^ { 2  }  +x  ^ { 3  }  -4x  ^ { 3  }  -6y  ^ { 2  }  +5-2-x  ^ { 3  } \\

-y^{2}-3x^{3}-6y^{2}+5-2-x^{3}  \\

-y^{2}-3x^{3}-6y^{2}+3-x^{3}  \\

-y^{2}-4x^{3}-6y^{2}+3  \\

-7y^{2}-4x^{3}+3  \\

\red{\boxed{{\textsf{Answer}}}}

-7y^{2}-4x^{3}+3  \\

\red{\texttt{{\textsf{XxXDxX}}}}

\orange{-}\red{-}\green{-}\blue{-}\orange{-}\orange{-}\red{-}\green{-}\blue{-}\orange{-}

6 0
3 years ago
I need help!!!! Please
Veronika [31]
1x100,000 = 100,000
3x10,000 = 30,000
9x1,000 = 9,000
8x100 = 800
5x10 = 50
2x1 = 2
Add these all together to get your answer.  Standard form is the form we usual write numbers in.  
4 0
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