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Semmy [17]
3 years ago
14

Find the slope and y-intercept 4x+2y=-6

Mathematics
2 answers:
EleoNora [17]3 years ago
8 0
<span>4x+2y=-6
2y = -4x - 6
  y = - 2x - 3
slope = -2
</span><span>y-intercept when x = 0
so y = -3

answer
slope = -2
</span><span>y-intercept (0,-3)</span>
skad [1K]3 years ago
3 0
Hi and good morning from Canada!

In order to find the slope and the y-intercept of 4x+2y=-6, we need to put this equation in y=mx+b form. This is because m=the slope and b=the y-intercept of a linear function, which is what this equation is (since the degree of the equation is a 1).

4x+2y=-6
2y=-4x-6
y=-4/2x-6/2
y=-2x-3

Therefore the slope is equal to -2 and the y-intercept is (0, -3).

Hope this helps!
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Step-by-step explanation:

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damaskus [11]

Answer & Step-by-step explanation:

The formula is given in the middle. You are supposed to insert the value of x into this formula to find the value of y (like in the first given example):

x=-2\\y=2(-2)+5\\y=-4+5\\y=1

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x=-1\\y=2(-1)+5\\y=-2+5\\y=3

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x=0\\y=2(0)+5\\y=0+5\\y=5

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x=1\\y=2(1)+5\\y=2+5\\y=7

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3 0
3 years ago
Find the equaton of the line passing through the points (2,11) and (-8, -19) y= ?x ?​
antoniya [11.8K]

Find the slope:

(-19 - 11) / (-8 - 2) = (-30/-10) = 3

Find the y intercept:

y = mx + b

11 = 3(2) + b

b= 5

So equation is:

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5 0
2 years ago
A manager in a call center needs to determine how many agents to schedule next week.
lukranit [14]

Answer:

Number of calls expected in next week by manager = 7940

Average Number of calls that call center agent will attend in an hour =7 calls

It is also given that, Call center remain open for 10 hours 5 days a week.

Also, it is given that, full time agents work 40 hours a week but are only on call for 35 hours per week  ,Part time agents work 20 hours a week but are only on calls 17 hours per week .

⇒Number of hours worked by full time agents × Number of calls attended in an hour × Number of full time agents + Number of hours worked by Part time agents × Number of calls attended in an hour × Number of Part time agents ≤ 7940

⇒35 × 7×Number of full time agents +17 × 7 ×Number of Part time agents ≤ 7940

Option A

⇒35×15×7+17×7×15

= 3675+1785

= 5460

Option B

⇒35 ×7×20+17×7×7

=4900 +833

= 5733

Option C

⇒35×20×7 +17×20×7

=4900+2380

=7280

Option D

⇒25 × 35×7+17×7×5

=6125 +595

=6720

Option E

⇒28×35×7+17×7×10

=6860+1190

=8050

Option E, ⇒ 28 full time agents and 10 part time agents , is best to meet the scheduling needs is most appropriate, that is nearer to 7940 calls.

7 0
3 years ago
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