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shutvik [7]
3 years ago
5

(a + b)(a2 – ab + b2) = a3 + b3

Mathematics
1 answer:
bearhunter [10]3 years ago
7 0

Answer:

a3 + b3 = a3 + b3

Step-by-step explanation:

I'm not sure what you are asking for but this equation is true if that's the problem.

Multiply all the variables and then combine like terms.

On the left side we end out as a3 + b3 which is equal to the right side. Hope this helps!

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How to simplify 5 cubed
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Answer:

125

Step-by-step explanation:

Steps to Solving the Problem

So let's say you have five friends who who are each going to pay you five dollars for the next five days. You can figure out how much money you will receive by calculating five cubed or five to the third power. This will tell us how much money you will get because you will multiply 5 by 5 by 5 or 5 cubed.

To start, you need to turn words into numbers by figuring out the base and exponent. An exponent is the number after the ^ which tells you how many times to multiply the base number by itself. The base number comes before the ^. When five is cubed, five is the base number which will show up before the ^.

Three is the exponent and will be the number after the ^. We know three is the exponent because of the word 'cubed,' which always represents the number three.

We can write out five cubed as:

5^3

Once the exponent and base are figured out, we need to write out the long version, which shows all the multiplication being done. In this case, the exponent of three tells us to multiply five by itself three times.

5 x 5 x 5

This shows us 5 friends multiplied by $5 multiplied by 5 days.

From here, multiply the numbers out to get the final answer. Multiply two numbers at a time to so you don't make a mistake.

5 x 5 = 25

25 x 5 = 125

6 0
3 years ago
Given points J(1, 4), A(3,5), and G(2, 1), what arethe coordinates of AJ'A'G' when reflected overthe x-axis?
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Reflection across the x-axis:

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y = − f ( x ) y = -f(x) y=−f(x) The concept behind the reflections about the x-axis is basically the same as the reflections about the y-axis.

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