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rosijanka [135]
3 years ago
15

The teacher has 15 gold prize ribbons, 22 blue ribbons, and 5e red ribbons. There are 12 boys and 18 girls in the class. If the

teacher divides the ribbons evenly among the students, how many ribbons will each student have? Write an expression using brackets, then solve your expression to find the answer.
Mathematics
1 answer:
natulia [17]3 years ago
4 0

Answer:

3

Step-by-step explanation:

Given

15 gold ribbons

22 blue ribbons

53 red ribbons

Total of 53 + 22 + 15 = 90 ribbons

Total number of students = 12 boys + 18 girls = 30 students.

If evenly divided, each student will have 90/30 = 3 ribbons

The expression to solve would basically be the amalgamation of what we did above:

(53 + 22 + 15)/(12+18)

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A scatter plot showed a positive correlation for 11 bowlers. As the number of strikes, s, a bowler made in a game increased, the
almond37 [142]

Answer:

s = 4

Step-by-step explanation:

The equation for the line of best fit for the data is p=25s+40.

Where p is no. of points and s is no. fo strikes

We need to find the number of strikes made by a bowler with 140 points.

Put p = 140

p=25s+40

140 = 25s+40

Subtract 40 to both sides,

140-40 = 25s+40-40

100 = 25s

⇒ s = 4

So, there are 4 strikes made by a bowler with 140 points.

5 0
3 years ago
A certain disease has an incidence rate of 0.1%. If the false negative rate is 8%
defon

Answer: 0.31 or 31%

Let A be the event that the disease is present in a particular person

Let B be the event that a person tests positive for the disease

The problem asks to find P(A|B), where

P(A|B) = P(B|A)*P(A) / P(B) = (P(B|A)*P(A)) / (P(B|A)*P(A) + P(B|~A)*P(~A))

In other words, the problem asks for the probability that a positive test result will be a true positive.  

P(B|A) = 1-0.02 = 0.98 (person tests positive given that they have the disease)

P(A) = 0.009 (probability the disease is present in any particular person)

P(B|~A) = 0.02 (probability a person tests positive given they do not have the disease)

P(~A) = 1-0.009 = 0.991 (probability a particular person does not have the disease)

P(A|B) = (0.98*0.009) / (0.98*0.009 + 0.02*0.991)

= 0.00882 / 0.02864 = 0.30796

*round however you need to but i am leaving it at 0.31 or 31%*

If you found this helpful please mark brainliest

3 0
3 years ago
Need help with this one, please only serious people answer or I’ll report your answer
frutty [35]
Vertical shift is -2. Horizontal shift is 1. Check the box that says reflect over x-axis. Horizontal shrink should be 4. Then to check if it looks right go to Desmos.com and in the graphing calculator put in y=-4(x-1)^2-2 and see if it looks like the one you did in your work
3 0
3 years ago
the waiter places a bowl of soup in front of lacy in a counterclockwise direction she passes the soup 90° the person receiving t
dybincka [34]

haifia is the answer did it on test

5 0
3 years ago
Aisha 3 times as many chocolates as Abdul. Together they have 24 chocolates, How many chocolates does each child have?
ch4aika [34]

Answer:

3x+X =24

4x=24

X=24/4

X=6

Aisha= 3x6

=18

Abdulla=1x6

=6

5 0
3 years ago
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