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ohaa [14]
3 years ago
12

At the park there is a pool shaped like a circle with diameter 22 yd. A ring-shaped path goes around the pool. Its width is 6 yd

.
We are going to give a new layer of coating to the path. If one gallon of coating can cover 5 yd", how many gallons of coating do we need? Note that coating
comes only by the gallon, so the number of gallons must be a whole number. (Use the value 3.14 for n).
Mathematics
1 answer:
Afina-wow [57]3 years ago
6 0

Answer:

106 gal

Step-by-step explanation:

step 1

Find the area of the path

we know that

The area of the path is given by the formula

A=\pi r_2^{2} -\pi r_1^{2}

A=\pi [r_2^{2} -r_1^{2}]

where

r_2 is the radius of the pool plus the width of the path

r_1 is the radius of the pool

we have

r_1=22/2=11\ yd ---> the radius is half the diameter

r_2=11+6=17\ yd

substitute

A=\pi [17^{2}-11^{2}]

A=168\pi\ yd^2

assume

\pi =3.14

A=168(3.14)=527.52\ yd^2

step 2

Find the gallons of coating needed

Divide the area of the path by 5

so

527.52/5=105.5\ gal

Round up

therefore

106 gal

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