Information communication technology (ICT) is a crucial tool to support effective communication and decision-making under complex and uncertain environments of disasters by enhancing cognitive capacity of emergency managers. With the continuous influence and evolution of communication technologies, information sharing and decision-making has drastically changed and affects each phase of emergency management. Researchers continue to investigate the relationship of human involvement for spreading public safety information through ICT. With each disaster holding diverse characteristics influencing prediction, detection, and specific activities required for prevention, mitigation, response and recovery, the need for interoperable and dependable communication infrastructure, a common operating picture, and supportive regulations, policies, and practice greatly increases. Although a national public safety communication system was proposed, there are implementation challenges between local, state, and federal agencies. This paper briefly examines the evolution of the use of ICT for public safety along with current trends, benefits and challenges, and future needs.
Answer:
Hacktivist
Explanation:
A hacktivist is a hacker who utilizes technology to announce a social, ideological, religious, or political message. In general, most hacktivism involves website defacement or denialof- service attacks.
The choices are a) credible website B)search log c) Boolean operator d) online database.
The answer is, d. Online database. There are already numerous online digital tools that can aid research. Examples are readcube, mendeley, google scholar. It helps you save and organize researches as well as automatically give bibliographies according to your need like APA and MLA. These tools can hold and save different information that researchers need.
Your answer would be A. Architects
Answer:
def most_frequent_letter():
file = open("words","r")
dWords = {}
for line in file:
line = line.rstrip()
words = line.split(" ")
for word in words:
counts = {}
for c in word:
counts[c] = counts.get(c, 0) + 1
dWords[word] = max(counts, key=counts.get)
return dWords
print(most_frequent_letter())
Explanation:
the file used was words in txt format and its contents are as follows:
hello aamir jan khan
parallelogram abdullah
anaconda ali
pycharm notebook
