A couple plans to have four children. Using a tree diagram , obtain the sample space. Then, find the probability that the family
has no boys.
1 answer:
Use b for boy and g for girl.
This is the resultant combinations:
b b b b
b b b g
b b g b
b b g g
b g b b
b g b g
b g g b
b g g g
g b b b
g b b g
g b g b
g b g g
g g b b
g g b g
g g g b
g g g g
If you count all the possibilities they are 16. Which is the same as 2^4 = 2*2*2*2, so I know that I didn't miss a combination.
The possibility of having no boys is one (g g g g combination) in 16, so the probability is 1 / 16 = 0,0625.
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Step-by-step explanation:
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Step-by-step explanation:
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