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vitfil [10]
4 years ago
14

1. Which equation shows a non-proportional

Mathematics
1 answer:
patriot [66]4 years ago
4 0

Answer:

Option D. y=2x+2

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line <u>and </u><u><em>the line passes through the origin</em></u>

<u><em>Verify each case</em></u>

case A) we have

y=-2x

Is a equation of the form y=kx

The value of k=-2

This equation represent a proportional relationship

case B) we have

y=2x

Is a equation of the form y=kx

The value of k=2

This equation represent a proportional relationship

case C) we have

y=-2x+0

The line passes through the origin, because the y-intercept is b=0

This equation represent a proportional relationship

case D) we have

y=2x+2

The line not passes through the origin, because the y-intercept is not equal to zero (b=2)

This equation not represent a proportional relationship

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Gavin uses more rope.

Step-by-step explanation:

Because 1/4>1/8, since 1/4=0.25 and 1/8=0.125.

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A group of friends wants to go to the amusement park. They have $87.25 to spend on parking and admission. Parking is $6.25, and
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Answer:

p = 3

Step-by-step explanation:

27p + 6.25 = 87.25

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Honors Geometry QUiz- Please Help
viktelen [127]

Answer:

QUESTION 2:

The area of the polygon is 21.5 units²

QUESTION 3:

The area of the combined figure is 12 + 18.25·π units²

QUESTION 4:

The area of the figure is 40 units²

QUESTION 5

The area of the compost shape is 40 in.²

Step-by-step explanation:

QUESTION 2.

The area of the polygon is given as follows;

The area of two triangles + The area of trapezoid

1/2×6×3 + 1/2×3×4 + 1/2×(6 + 7) = 21.5 units²

QUESTION 3

The diameter of the semicircle, 'd', is given as follows;

d = √(8² + 3²) = √73

The area of the semicircle = π·d²/4 = π·73/4 = 18.25·π unit²

The area of the right triangle beside the semicircle is given as follows;

1/2 × 8 × 3 = 12 unit²

The area of the combined figure = The area of the semicircle + The area of the right triangle

∴ The area of the combined figure = 12 + 18.25·π units²

QUESTION 4:

The dimensions of the parallelogram are;

Width, W = √(4² + 1²) = √(17)

Length, L = √(8² + 2²) = √(68)

The area of the parallelogram, A_R = W × L = √(17) × √(68) = √(17 × 68) = 34

The area of the parallelogram, A_R = 34 units²

The length of a parallel side, 'A', of the parallelogram is A = 6

The height of the parallelogram, is h = 1

The area of the parallelogram is A = B·h = 6 × 1 = 6 units²

The area of the figure is the sum of the area of the rectangle and the area of the parallelogram

Therefore, we have;

The area of the figure = 34 units² + 6 units² = 40 units²

QUESTION 5

The composite shape consists of a triangle and a rectangle

Therefore, we have;

The area of the rectangle = 5 in. × 7 in. = 35 in.²

The area of the triangle = 1/2 × 2 in. × 5 in. = 5 in.²

The area of the compost shape = The area of the rectangle + The area of the triangle

∴ The area of the compost shape = 35 in.² + 5 in.² = 40 in.²

The area of the compost shape = 40 in.².

5 0
3 years ago
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