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viktelen [127]
4 years ago
7

The manager of a major retail store has taken a random sample of 25 customers. The average sale was $52.50. The population stand

ard deviation is known to be $6.10. The manager would like to determine whether or not the mean sales by all customers are significantly more than $50. What is the p-value for the test?
a. .05
b. .02
c. 2.50

Mathematics
1 answer:
zimovet [89]4 years ago
5 0

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

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Joe bikes at the speed of 30 km/h from his home toward his work. If Joe's wife leaves home 5 mins later by car, how fast should
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Answer:

Joe's wife must drive at a rate of 45km/hour.

Step-by-step explanation:

We are given that Joe leaves home and bikes at a speed of 30km/hour. Joe's wife leaves home five minutes later by car, and we want to determine her speed in order for her to catch up to Joe in 10 minutes.

Since Joe bikes at a speed of 30km/hour, he bikes at the equivalent rate of 0.5km/min.

Then after five minutes, when his wife leaves, Joe is 5(0.5) or 2.5 km from the house. He will still be traveling at a rate of 0.5km/min, so his distance from the house can be given by:

2.5+0.5t

Where <em>t</em> represents the time in minutes after his wife left the house.

And since we want to catch up in 10 minutes, Joe's distance from the house 10 minutes after his wife left will be:

2.5+0.5(10)=7.5\text{ km}

Let <em>s</em> represent the wife's speed in km/min. So, her speed times 10 minutes must total 7.5 km:

10s=7.5

Solve for <em>s: </em>

<em />\displaystye s=0.75\text{ km/min}<em />

Thus, Joe's wife must drive at a rate of 0.75km/min, or 45km/hour.

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How to factor 15m^2-12m^3
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Read 2 more answers
A stone is thrown vertically upwards with an initial velocity 20m/s. Find the maximum height it reaches and the time taken by it
Gemiola [76]

Answer:

The maximum height it reaches is 20 meters

The time taken by it to reach the height is 2 seconds

Step-by-step explanation:

The formula of the height of the stone is h = u t - \frac{1}{2} g t², where

  • t is the time to reach the height h
  • u is the initial velocity
  • g is the acceleration of gravity

∵ A stone is thrown vertically upwards with an initial velocity of 20 m/s

∴ u = 20 m/s

∵ g = 10 m/s²

→ Substitute them in the equation above

∴ h(t) = 20t - \frac{1}{2} (10) t²

∴ h(t) = 20t - 5t²

→ Arrange the terms of the right side according to the greatest power of t

∴ h(t) = -5t² + 20t

To find the maximum height and the time of it find the vertex of the quadratic function (m, k), where m = \frac{-b}{2a} and k is the value of h at t = m, a is the coefficient of t² and b is the coefficient of t

∵ The coefficient of t² is -5

∴ a = -5

∵ The coefficient of t is 20

∴ b = 20

→ Use them to find h

∵ m = \frac{-20}{2(-5)} = \frac{-20}{-10} = h

∴ m = 2

→ Substitute it in the equation above to find k

∵ h(m) = k

∵ k = -5(2)² + 20(2)

∴ k = -5(4) + 40

∴ k = -20 + 40

∴ k = 20

∴ The coordinate of the vertex of the function are (2, 20)

→ m represents the time of the maximum height and k represents

  the maximum height

∴ The maximum height it reaches is 20 meters

∴ The time taken by it to reach the height is 2 seconds

5 0
3 years ago
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