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Marta_Voda [28]
3 years ago
6

A boat costs $12,050 and decreases in value by 12% per year. How much will the boat be worth after 9 years?

Mathematics
2 answers:
Rainbow [258]3 years ago
5 0

For this case we have the following expression:

y = A (b) ^ x

Where,

  • <em>A: initial value </em>
  • <em>b: rate of change </em>
  • <em>x: number of years </em>
  • <em>y: future value </em>

Therefore, replacing values we have:

y = 12050 * (0.88) ^ 9\\y = 3813.56

Answer:

The boat will be worth after 9 years about:

B $ 3,813.56

andreyandreev [35.5K]3 years ago
3 0
B $3,813.56 is the correct answer

1 year = $10,604
2 years = $9,331.52
3 years = $8,211.74
4 years = $7,226.33
5 years = $6,359.17
6 years = $5,596.07
7 years = $4,924.54
8 years = $4,333.60
9 years = $3,813.56









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15% of 20 is what number?
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3 years ago
Kelly invested her savings of $4800. she invested part in mutual funds, at 9% per year, and the rest in GIC's, at 10% per year.
Aneli [31]

Answer:

For the 9% she invested $2,300

For the 10% she invested $2,500

Step-by-step explanation:

Let the amount invested be $x and $y in both cases respectively

Since the total invested is $4,800

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x + y = 4800 ••••••••••••(i)

Now let’s have a look at the interests.

For the 9%

Interest would be 9/100 * amount invested

= 9/100 * x = 9x/100

For the 10%, interest would be

10/100 * y = 10y/100

Adding both will give a total of 457

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multiply through by 100

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From equation i, we can write x = 4800 - y

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9(4800-y) + 10y = 45700

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5 0
3 years ago
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Answer:

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I hope it will help you

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