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3 years ago

14

Lamar rented a truck for one day. There was a base fee of $18.99, and there was an additional charge of 78 cents for each mile d

riven, Lamar had
to pay $232.71 when he returned the truck. For how many miles did he drive the truck?

1 answer:

Neporo4naja [7]3 years ago

5 0

Answer: 274 miles.

Step-by-step explanation: subtract 232.71 by 18.99. the divide the outcome by .78.

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Hal is asked to write an exponential function to represent the value of a $10,000 investment decreasing at 2% annually. What mul

Inga [223]

Answer

The multiplicative rate of change that should be in Hal’s function = 49/50=0.98

=9.8×10⁻¹

Explanation

The investment of $10,000 decreases by 2% every year. So the following year is usually (100 - 2)=98% of the previous year. This is a geometric progression.

In this case the first term = 10000

The second term = 98% × 10000 = 9800.

The common ratio = 9800/10000=49/50

The multiplicative rate of change that should be in Hal’s function = 49/50=0.98.

The equation of the exponential rate would be;

10,000ₓ0.98ⁿ.

where n is the number years.

Hope his helps! ;)

8 0

3 years ago

What multiplication problem is equivalent to 3 3/8 divide by 3/8

Anni [7]

The expression $3\frac{3}{8}\div \frac{3}{8}$ can be written in multiplication problem as: $3\frac{3}{8}\times \frac{8}{3}$ or $\frac{27}{8}\times \frac{8}{3}$

Step-by-step explanation:

We need to find What multiplication problem is equivalent to $3\frac{3}{8}\div \frac{3}{8}$

We are given: $3\frac{3}{8}\div \frac{3}{8}$

Writing it in multiplication problem.

When division sign is changed to multiplication sign, the fraction is reciprocated.

$3\frac{3}{8}\div \frac{3}{8}$

Converting division into multiplication

$3\frac{3}{8}\times \frac{8}{3}$

or we can write as:

$\frac{27}{8}\times \frac{8}{3}$

So, the expression $3\frac{3}{8}\div \frac{3}{8}$ can be written in multiplication problem as: $3\frac{3}{8}\times \frac{8}{3}$ or $\frac{27}{8}\times \frac{8}{3}$

Keywords: Solving Fractions

Learn more about Solving Fractions at:

#learnwithBrainly

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3 years ago

Max claims that a point on any line that is perpendicular to a segment is equidistant from a segment's endpoints. Charlene claim

yan [13]

Answer:

Charlene claim is true.

Step-by-step explanation:

Max claims that a point on any line that is perpendicular to a segment is equidistant from a segment's endpoints.

It is not necessary as shown in the diagram (a).

Charlene claims that the line must be a perpendicular bisector for a point on the line to be equidistant from a segment's endpoints.

It is true as shown in the diagram (b).

So, Charlene claim is true.

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2 years ago

Which of the following statements is true about

lions [1.4K]

Answer:

The y-axis stays the same

Step-by-step explanation:

:)

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3 years ago

What is 5/20 as a percent if you could give an explanation that would be good but if not thats okay

Liono4ka [1.6K]

5/20 can also be represented as 25/100 or 25%. The can be done by multiplying the top and bottom both by 5 and then dividing our numerator (25) by our denominator(100) to get the %.

3 0

3 years ago

Read 2 more answers