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Feliz [49]
3 years ago
5

A quadrilateral has vertices A(11, -7), B(9, -4), C(11, -1), and D(13, -4). Quadrilateral ABCD is a . If the vertex C(11, -1) we

re shifted to the point C′(11, 1), quadrilateral ABC′D would be a .
Mathematics
1 answer:
rosijanka [135]3 years ago
5 0

Answer:

Quadrilateral A(11, -7), B(9, -4), C(11, -1), and D(13, -4) forms a rhombus.

Quadrilateral A(11, -7), B(9, -4), C'(11,1), and D(13, -4) forms a kite.

Step-by-step explanation:

Rhombus is a quadrilateral whose all sides have equal length.

Kite is a quadrilateral whose four sides can be grouped into two pairs of equal-length sides which are adjacent to each other.

The quadrilateral formed by the vertices A(11, -7), B(9, -4), C(11, -1), and D(13, -4) would result in a rhombus (see figure below) because it had four equal sides.

If C(11,-1) is shifted to the point C'(11,1), it would become a kite (see figure below) because it has two pairs of equal sides.

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7y + 4x - 10 + 5y - 5 + x
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Answer:

hope it helps u

Step-by-step explanation:

7y + 4x - 10 + 5y - 5 + x

= 7y+5y+4x+x–10–5

= 12y+5x–15

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3 years ago
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2 years ago
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elena-14-01-66 [18.8K]
First of all, we know that
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Corporation A: 3.2×10^5
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Lastly,
To find “ How many times greater is corporation A’s land than corporation B’s land ", take:
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5 0
3 years ago
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FinnZ [79.3K]

Answer:

The remainder is 4.

Step-by-step explanation:

Note: This question is not correctly stated. It is therefore correctly restated before answering the question as follows:

When 17 is divided by k; where k is a positive integer less than 17, the remainder is 3. What is the remainder when the sum of the possible values of k is divided by 17?

The explanation of the answer is now given as follows:

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Therefore, we have:

Sum of the possible values of k = 7 + 14 = 21

Also, we have:

Sum of the possible values of k divided by 17 = 21 / 17 = 1 with a remainder of 4.

Therefore, the remainder is 4 when the sum of the possible values of k is divided by 17.

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