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3 years ago

In which case would it be necessary to find the area of this circle

Mathematics

1 answer:

9966 [12]3 years ago

7 0

You need to know the area if you're going to
1st selection: cover the surface of the dartboard.

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Please help me please!!

Tpy6a [65]

Answer:

Extracting out that inner right angle.

Hypotenuse = 8

Height = h

Adjacent :

$= \frac{10}{5} = 2$

Height, h :

${ \tt{h = \sqrt{ {8}^{2} - {5}^{2} } }} \\ { \tt{h = \sqrt{64 - 25} }} \\ { \tt{h = \sqrt{39} }} \\ the \: height \: is \: { \boxed{6.2}} \: units$

3 0

3 years ago

A savings account increases from $200 to $210 what is the percent increase of the savings in the account.

Illusion [34]

Answer:

Step-by-step explanation:

10/200 × 100 = 5

hope this helps...

7 0

2 years ago

What is 5 = p over 4

Gnoma [55]

Since it's p over four, which is a fraction, multiply each side by four. p = 20

3 0

3 years ago

One of the tables shows a proportional relationship. Graph the line representing the proportional relationship from this table i

Mkey [24]

Answer:

Table C

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

Find the value of the constant of proportionality in each table

Table A

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-3$ ------> $k=-3/-1=3$

This table has different values of k

therefore

the table A does not represent a proportional relationship

Table B

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=3$ ------> $k=3/1=3$

This table has different values of k

therefore

the table B does not represent a proportional relationship

Table C

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=2$ ------> $k=2/1=2$

For $x=2, y=4$ ------> $k=4/2=2$

This table has the same value of k

therefore

the table C represent a proportional relationship

Table D

For $x=-2, y=-4$ ------> $k=-4/-2=2$

For $x=-1, y=-2$ ------> $k=-2/-1=2$

For $x=1, y=2$ ------> $k=2/1=2$

For $x=2, y=6$ ------> $k=6/2=3$

This table has different values of k

therefore

the table D does not represent a proportional relationship

3 0

3 years ago

Read 2 more answers

(a+b)^2 hihhhhhhhhhhhhhhhhhhhh

OverLord2011 [107]

Answer:

a^2 + 2ab + b^2

Answered by Gauthmath

3 0

3 years ago

Read 2 more answers