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jonny [76]
3 years ago
13

In which case would it be necessary to find the area of this circle

Mathematics
1 answer:
9966 [12]3 years ago
7 0
You need to know the area if you're going to
  1st selection: cover the surface of the dartboard.
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How do you solve this? r^2+32=12r
Andre45 [30]

Answer:

r = {-8, -4}

Step-by-step explanation:

Simplifying

r2 = -32 + -12r

Solving

r2 = -32 + -12r

Solving for variable 'r'.

Reorder the terms:

32 + 12r + r2 = -32 + -12r + 32 + 12r

Reorder the terms:

32 + 12r + r2 = -32 + 32 + -12r + 12r

Combine like terms: -32 + 32 = 0

32 + 12r + r2 = 0 + -12r + 12r

32 + 12r + r2 = -12r + 12r

Combine like terms: -12r + 12r = 0

32 + 12r + r2 = 0

Factor a trinomial.

(8 + r)(4 + r) = 0

Subproblem 1

Set the factor '(8 + r)' equal to zero and attempt to solve:

Simplifying

8 + r = 0

Solving

8 + r = 0

Move all terms containing r to the left, all other terms to the right.

Add '-8' to each side of the equation.

8 + -8 + r = 0 + -8

Combine like terms: 8 + -8 = 0

0 + r = 0 + -8

r = 0 + -8

Combine like terms: 0 + -8 = -8

r = -8

Simplifying

r = -8

Subproblem 2

Set the factor '(4 + r)' equal to zero and attempt to solve:

Simplifying

4 + r = 0

Solving

4 + r = 0

Move all terms containing r to the left, all other terms to the right.

Add '-4' to each side of the equation.

4 + -4 + r = 0 + -4

Combine like terms: 4 + -4 = 0

0 + r = 0 + -4

r = 0 + -4

Combine like terms: 0 + -4 = -4

r = -4

Simplifying

r = -4

Solution

r = {-8, -4}

3 0
3 years ago
Find the experimental probability Roll dice 1,3,3,4,4 P(1)= I’ll give brainleist
-Dominant- [34]

Answer:

\mathrm{P(1)\:}=\frac{1}{5}

Step-by-step explanation:

There are simply 5 possible values in the given set. Out of these, only one of these is the number 1. Therefore, the probability a 1 is drawn (P(1)) is \fbox{$\frac{1}{5}$}.

5 0
3 years ago
Read 2 more answers
Please answer quick!!
rewona [7]

Answer: B

Step-by-step explanation:

\frac{2}{7k}(k-7)

\frac{2k-14}{7k}

\frac{2k}{7k}-\frac{14}{7k}

\frac{2}{7}-\frac{2}{k}

7 0
3 years ago
How do you do this? I can't remember
Hitman42 [59]
14.75 depending on if the model is 8 & the actual is 1 in the 1:8 scale factor because you would just multiply the actual by 8 because it is the scale factor. the answer could also be .23 is the model is 1 & the actual is 8 because you would divide the actual by 8! hope this helps!!
3 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%7B%7D%5E%7B2%7D%20-%204%20%7D%7B%20%5Csqrt%7Bx%20%7B%7D%5E%7B2%7D%20-%206x%2
Nimfa-mama [501]

First of all, we can observe that

x^2-6x+9 = (x-3)^2

So the expression becomes

\dfrac{x^2-4}{\sqrt{(x-3)^2}} = \dfrac{x^2-4}{|x-3|}

This means that the expression is defined for every x\neq 3

Now, since the denominator is always positive (when it exists), the fraction can only be positive if the denominator is also positive: we must ask

x^2-4 \geq 0 \iff x\leq -2 \lor x\geq 2

Since we can't accept 3 as an answer, the actual solution set is

(-\infty,-2] \cup [2,3) \cup (3,\infty)

7 0
3 years ago
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