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True [87]
4 years ago
6

Why is it important to solve an equation for a specific variable?

Mathematics
1 answer:
Svetllana [295]4 years ago
8 0
It all depends on the importance of the variable its self. Its important to solve it so you know what the variable is and its important to solve one at a time because its impossible to solve a variable completely if you have two of them
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Evaluate the expression x ÷ y for x = 8 and y = 16.
daser333 [38]

Answer:

Step-by-step explanation:

hello :

x ÷ y for x = 8 and y = 16 means : 8/16 = 8/(2×8) = 1/2

7 0
4 years ago
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The molarity of a solute in solution is defined to be the number of moles of solute per liter of solution (1 mole = 6.02 × 1023
KengaRu [80]

Answer:

a) 0.65

b) 0.1581

Step-by-step explanation:

We are given the following in the question:

Distribution of X:

Mean = 0.125

Standard deviation = 0.05

Distribution of Y:

Mean = 0.350

Standard deviation = 0.10

Solution:

M = X + 1.5Y

a) mean of M

\mu_M = \mu_X + 1.5(\mu_Y) = 0.125 + 1.5(0.350) = 0.65

b) standard deviation of M

If X and Y are independent then,

Var(X+Y) = Var(X) + Var(Y)\\Var)aX) = a^2Var(X)

Var(M) = Var(X+1.5Y)\\Var(M) =Var(X) + (1.5)^2Var(Y)\\Var(M) = (0.05)^2 + (1.5)^2(0.10)^2 = 0.025

Standard deviation of M =

=\sqrt{Var(M)} = \sqrt{0.025} = 0.1581

4 0
3 years ago
How can you find the distance from a point to the x axis
mojhsa [17]

Answer:

be a big brain

Step-by-step explanation:

7 0
3 years ago
Victoria sets a goal for the number of boxes of Girl Scout cookies she wants to sell.So far, she's solved 33 boxes.I this is nin
oksian1 [2.3K]
Her goal is 120 boxes

I hoped this helped :)
7 0
3 years ago
A chemist is using 351 milliliters of a solution of acid and water. If 14.1% of the solution is acid, how many milliliters of ac
stepan [7]

49.491 millimeters of acid is present

<em><u>Solution:</u></em>

Given that, chemist is using 351 milliliters of a solution of acid and water

14.1% of the solution is acid

To find: Milliliters of acid present

From given statement,

Solution of acid and water = 351 ml

14.1% of the solution is acid, which means that 14.1 % of 351 ml is acid

Therefore,

Milliliters of acid present = 14.1 % of 351 ml

Here "of" means multiplication

Therefore,

\text{ Milliliters of acid present } = 14.1 \% \times 351

\rightarrow 14.1 \% \times 351\\\\\rightarrow \frac{14.1}{100} \times 351\\\\\rightarrow 0.141 \times 351 = 49.491

Thus 49.491 millimeters of acid is present

6 0
4 years ago
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