Answer:
the point is (3, 3) . . . . . . y = 3
Step-by-step explanation:
Write the point-slope equation of the line through the point you know. Then evaluate that equation for x=3 to see what the value of y is.
Point-slope form:
y = m(x -h) +k . . . . slope m through point (h, k)
y = -1/2(x -9) +0 . . . . line with slope -1/2 through point (9, 0)
For x=3, the value of y is ...
y = -1/2(3 -9) + 0 = -1/2(-6) = 3
The value of y is 3.
The perimeter of a semicircle consists of two parts. (the curve and bottom)
That curve is half the distance around the circle, since it's been split in half.
The distance around a circle, the circumfrence, is equal to 2πr, where r is the radius of that circle. In this case, the circumfrence of the entire circle would be 16π. and so that curve would have a length of just 8π.
Using 3.14 for π, 8π = 8×3.14 = 25.12.
As for the flat part, that is the diameter (distance across) our circle.
The radius is the distance from the center of a circle to its edge, and always has half the length of the diameter. (you can break the diameter down into two radii)
If our radius is 8 meters, our diameter (the flat part of that semicircle) must be 16.
Now we add up the two parts of the perimeter...25.12 + 16 = 41.12.
Answer:
-2
Step-by-step explanation:
Making the value of 'a' smaller, but still positive, will make the graph be compressed vertically.
Let's say a = 1 is the initial value. If we update it to a = 0.5, then the graph will be half as tall as it used to be, so it's compressed by a factor of 1/0.5 = 2.
The value of b determines the period of the sinusoidal function.
Answer:
14.52 seconds.
Step-by-step explanation:
We have been given that the height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation 
. We are asked to find the time, when the rocket will hit the ground.
We know that the rocket will hit the ground, when height will be 0. So to find the time when rocket will hit the ground, we will substitute 
in our given equation as:
Let us solve for x using quadratic formula.
Upon rounding to nearest 100th of second, we will get:
Since time cannot be negative, therefore, the rocket will hit the ground after 14.52 seconds.
