Answer:
C
Step-by-step explanation:
(2,3) to (5,-4) its (3,-7) so you jus add (3,-7) to (6,-2) and it gives you (9,-9)
I dont know if it makes sense but yea
Answer:
y = -2x + 1
Step-by-step explanation:
Y2 - Y1 / X2 - X1
-3 - 1 / 2 - 0
-4 / 2
= -2
y = -2x + b
-3 = -2(2) + b
-3 = -4 + b
1 = b
y = -2x + 1
Answer:
318
Step-by-step explanation:
318 is the required answer
I hope it helped you
So given Figure we need to find total surface area
=Area(ABCD)+Area(BCRQ)+Area(QRSP)+Area(ADSP)+Area(ABQP)+Area(DCRS)
=(AB×BC)+(BC×CR)+(QR×RS)+(AD×DS)+(AB×BQ)+(DC×CR)
From figure,
AB=DC=PQ=SR=9 cm
BQ=CR=AP=DS=11 cm
BC=AD=QR=SP=3 cm
On substituting these values We get
Surface Area=(9×3)+(3×11)+(9×3)+(11×3)+(9×11)+(9×11)
=27+33+27+33+99+99=318
I hope it helped you
Answer:
Let's define the variables:
A = price of one adult ticket.
S = price of one student ticket.
We know that:
"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."
1*A + 6*S = $69
"The school took in $150 on the second day by selling 7 adult tickets and student tickets"
7*A + 7*S = $150
Then we have a system of equations:
A + 6*S = $69
7*A + 7*S = $150.
To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:
A = $69 - 6*S
Now let's replace this in the other equation:
7*($69 - 6*S) + 7*S = $150
Now we can solve this for S.
$483 - 42*S + 7*S = $150
$483 - 35*S = $150
$483 - $150 = 35*S
$333 = 35*S
$333/35 = S
$9.51 = S
That we could round to $9.50
That is the price of one student ticket.
It's hard to have √2 points in a basketball game (or almost any game). The number of points scored is a discrete random variable, usually restricted to non-negative integers.
