During which interval was the bicyclist's speed the fastest

Help, I have to turn this in tomorrow ... is this correct??

Natali5045456 [20]

Answer: I think so that's what i would put

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Please help no links or i will report

ELEN [110]

9514 1404 393

Answer:

D. (1.6 + 3) × (4 − 2) ÷ 2

Step-by-step explanation:

The order of operations requires that multiplication and division be done in order of appearance, left to right, before addition and subtraction. Operations in parentheses take priority.

To get 4.6, you need to add 3 to 1.6. The various forms of 3×4-2÷2 all give 12-1 = 11, not 3.

The grouping that gets it right is ...

(1.6 + 3) × (4 − 2) ÷ 2

= 4.6×2÷2

= 9.2÷2

= 4.6

6 0

3 years ago

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Graph P=6d and P=5d+15

Zielflug [23.3K]

9514 1404 393

Answer:

see attached

Step-by-step explanation:

The point of intersection is found by equating the expressions for P:

6d = 5d +15

d = 15

p = 6d = 6·15 = 90

The point of intersection of the graphs is (15, 90).

The first equation graphs as a line with slope 6 through the origin.

The second equation graphs as a line with slope 5 through point (0, 15).

It is inconvenient to graph p and d using the same scale, so the attache graph has the vertical scale compressed somewhat.

8 0

3 years ago

3(x + 2) + x = 2x + 16

algol [13]

Answer:Polynomial equation solver

Standard form:

2x − 10 = 0

Factorization:

2(x − 5) = 0

Solutions:

x = 10

2

= 5

-5

5

10

15

-20

-10

10

20

Step-by-step explanation:

4 0

3 years ago

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In 2008, there were 507 children in Arizona out of 32,601 who were diagnosed with Autism Spectrum Disorder (ASD) ("Autism and de

Naily [24]

Answer:

$z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318$

$p_v =P(Z>0.318)=0.375$

So the p value is a very high value and using the significance level provided $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

Step-by-step explanation:

Data given and notation

$X_{1}=507$ represent the number of children diagnosed with Autism Spectrum Disorder (ASD) in Arizona

$n_{1}=32601$ sample elected from arizona

$\hat p_{1}=\frac{507}{32601} =0.0156$ represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona

$p_{2}=\frac{1}{88}= 0.0114$ represent the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in the nation

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if that the incident of ASD is more in Arizona than nationally, the system of hypothesis are:

Null hypothesis: $p_{1} \leq p_{2}$

Alternative hypothesis: $p_{1} > p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{507+1}{32601 +88}=0.01554$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.0156-0.0114}{\sqrt{0.01554(1-0.01554)(\frac{1}{32601}+\frac{1}{88})}}=0.318$

Statistical decision

The significance level provided is $\alpha=0.01$ , and we can calculate the p value for this test.

Since is a one right sided test the p value would be:

$p_v =P(Z>0.318)=0.375$

So the p value is a very high value and using the significance level provided $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the proportion of children diagnosed with Autism Spectrum Disorder (ASD) in arizona is not significantly higher than the national incident rate at 1% of significance.

5 0

3 years ago