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stich3 [128]
4 years ago
12

Please help I don’t know how to simplify this expression

Mathematics
1 answer:
Rus_ich [418]4 years ago
4 0
2\sqrt{12} \times -6\sqrt{2} =

= 2 \times (-6)\sqrt{12 \times 2}

= -12 \sqrt{24}

= -12 \sqrt{4 \times 6}

= -12 \sqrt{4} \times \sqrt{6}

= -12 \times 2 \times \sqrt{6}

= -24 \sqrt{6}
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A smaller square garden has an area of 400 square meters . What is the length of one side of the garden?
crimeas [40]

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600,000 1/10 of what? Please help!!
igor_vitrenko [27]
600000 is 1/10 of "x", that means x = 10/10 or a whole, what is "x"?

\bf \begin{array}{ccll}
amount&fraction\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
600000&\frac{1}{10}\\\\
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8 0
4 years ago
For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at
GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}

Now, let's add the components of the same direction:

\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}

To find the resultant bearing (theta), we can use the formula below:

\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0
2 years ago
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