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MrMuchimi
4 years ago
10

What is 4/5 ratio in hours ?

Mathematics
2 answers:
Serjik [45]4 years ago
6 0
4:5 Shrink 2.5 times = 1.6:2
If rounded:

4:5 Shrink 2.5 times = 2:2
mihalych1998 [28]4 years ago
4 0

Answer:

60-12= 48 min. or .8 hours

Step-by-step explanation:

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4.19 square inches.Hope i helped!
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Which Expressions are Equivalent?
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A. 3x-7y and -7+3x that is the correct answer
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Three of the kids on the tilt-O-Whirl threw up when they got off the ride. This is one-fifth of the kids on the ride. Write an e
hichkok12 [17]

Answer:

3 is 1/5 so 3*5 is how many kids are on the ride.

3 * 5 = 15. There are 15 kids on the ride, but the question's answer would just be 3*5.

7 0
3 years ago
Test the claim below about the mean of the differences for a population of paired data at the level of significance α Assume the
Evgen [1.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  correct option is F

t =  1.17

t_ {\alpha , df} =t_ {0.10 , 8} = 1.86

Since the test statistics<u> is outside </u>the rejection region , <u>we fail to reject </u>the null hypothesis ,There<u> is no</u>  statistically significant evidence to reject the claim

Step-by-step explanation:

From the question we are told that

    The  claim is  \mu =  0

Hence  

      The  null hypothesis is  H_o  :  \mu = 0

       The  alternative is  H_a  :  \mu  \ne  0

Generally the test statistics is mathematically represented as  

                 t =  \frac{\= d - \mu_d }{ \frac{s_d}{ \sqrt{n} } }

=>              t =  \frac{3.5 -0 }{ \frac{8.94}{ \sqrt{9} } }

=>              t =  1.17

Generally the degree of freedom is mathematically represented as

      df  =  n- 1

      df  =  9 -  1

      df  =  8

From the student t-distribution table  the critical value of  \alpha at a degree of freedom of  8 is  

          t_ {\alpha , df} =t_ {0.10 , 8} = 1.86

Since the t_ {\alpha , df} is  outside the rejection region , we fail to reject the null hypothesis ,There is no sufficient evidence to reject the claim

4 0
3 years ago
A lifeguard fills a pool with water at a constant rate. After 12 hour, 13 of the pool is filled. At this rate, what fraction of
strojnjashka [21]

At the considered rate the fraction of pool that is filled per hour is 13/12

<h3>How to measure the rate of change of something as some other value changes?</h3>

Suppose that we have to measure the rate of change of y as x changes, then we have:

Rate = \dfrac{y_2 - y_1}{x_2 - x_1}

where we have

\rm when \: x=x_1, y = y_1\\when\: x = x_2, y= y_2

Remember that, we divide by the change in independent variable so that we get some idea of how much the dependent quantity changes as we change the independent quantity by 1 unit.

(5 change per 3 unit can be rewritten as 5/3 change per 1 unit)


For the considered case, we can take time spent as difference of independent variable, and the amount of pools filled as the corresponding difference of the dependent variable.

in 12 hour time interval total 13 pools were filled.

That means

Rate of filling the pool is 13 pools per 12 hours or \dfrac{13}{12} pools per hour.

Thus, at the considered rate the fraction of pool that is filled per hour is 13/12

Learn more about rate of change here:

brainly.com/question/11484885

4 0
2 years ago
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