Answer:
2 7/12
Step-by-step explanation:
−512−−93=?
Since the the second fraction is negative and you are subtracting, remove the negative sign and switch the operation to addition.
The equivalent equation is
−512+93=?
The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.
LCD(-5/12, 9/3) = 12
Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.
(−5/12×1/1)+(9/3×4/4)=?
Complete the multiplication and the equation becomes
−5/12+36/12=?
The two fractions now have like denominators so you can subtract the numerators.
Then:
−5+36/12=31/12
This fraction cannot be reduced.
The fraction
31/12
is the same as
31÷12
Convert to a mixed number using
long division for 31 ÷ 12 = 2R7, so
31/12=2 7/12
Therefore:
−5/12−−9/3=2 7/12
It’s times by 5 just graph the points on the graph then count how much the rise and run is and then you have your slop
Answer:

This is because modulus number will be always positive
Hope this is correct and helpful
HAVE A GOOD DAY!
Answer:
NO, as per study, I cant see any other problem than the sample size in the procedure.
From the graph there is a slight quadratic relationship between temperature and number of O-rings.
As in the graph, we can see that above 50°F but below 55°F number of O-rings in 3 but after 55°F as temperature goes on increasing the number of O-rings decreases and remains constant up to 70°F and above 70°F the number of O-rings increases to 2. Hence, we can say that there is a relationship between temperature and number of O-rings.
If we want to fit a linear regression through these seven observations, the slope would be positive as linear regression line passes through the average.
Looking at the relationship, slope must be significantly different from zero as there is a relationship between two variables, where as slope significantly zero implies no relationship. However, we have only seven points so drawing a conclusion is difficult as the nature of the relationship is not clearly visualized by this graph.
Let's replace the first, second, third, and home with letters.
first base = F
second base = S
Third base = T
home base = H
We have two triangles, ΔHTS and ΔHFS
We know HS = HS because it's a shared side.
We know FS = TS
We know that ∠HST and ∠HSF are equal.
Because of SAS, the two triangles are congruent.
According to CPCTC, TH must be congruent to FH.
Thus, the distance from home plate to third base and the distance from home plate to first base must be the same.
Have an awesome day! :)