1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

2.

3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
= -3/2 * -5 1/4
convert 5 1/4 to improper fraction
= -3/2 * -21/4
multiply numerators; multiply denominators
= (-3*-21)/(2*4)
multiply in parentheses
= 63/8
convert back to mixed number
= 7 7/8
ANSWER: Since the exact answer is the mixed number 7 7/8, a reasonable estimate is 8.
Hope this helps! :)
In order to keep the constant, the same and not vary there must be an indirect or inverse relationship to always maintain the value of k.
Thus both P and V are inversely related to each other.
The best and most correct answer among the choices provided by the question is the fourth choice "d=square root of (x^2+x^1)+(y^2-y^1)^2"
The law of cosines<span> for calculating one side of a triangle when the angle opposite and the other two sides are known. Can be used in conjunction with the </span>law<span> of sines to find all sides and angles. </span>
I hope my answer has come to your help. God bless and have a nice day ahead!