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lys-0071 [83]
3 years ago
14

A marble is selected at random from a jar containing 2 red marbles, 6 yellow marbles, and 5 green marbles. What is the probabili

ty that a) the marble is red? b) the marble is not yellow? ) the marble is either red or green? d) the marble is neither red nor green?
Mathematics
1 answer:
zalisa [80]3 years ago
3 0

The 2 red marbles plus 6 yellow and 5 green equal 13 total marbles.

A) There are 2 red marbles out of the total number so 2/13 or about 15.4%

B)The colors that are not yellow are red and green. 2 Red+5 Green=7. 7/13 or about 53.8%.

C)Same as B

D)The only color not red or green is yellow. There are 6 yellow so 6/16 or 46.2%.

<u>Hope this helps :-)</u>

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A school has 300 students.If the ratio of boys to girls is 31 to 44, how many more girls are there in the school?
garri49 [273]

Answer:

there would be 52 more girls I think

Step-by-step explanation:

let x = multiplier then

31x =number of boys

44x = number of girls

Boys + girls = 300

44x + 31x =300

75x = 300

x = 300/75

x = 4 is the multiplier

therefore:

44*4 = 176 girls

31*4 = 124 boys

dif = 52 more girls than boys

hope this helped :)

5 0
3 years ago
Write an expression based on description; use grouping symbols
Harman [31]

Answer:

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8 0
3 years ago
Ms. Jan brought in cookies for her class. She gave out half of them in the morning. At lunch, she gave out 12 more. She then had
Olegator [25]

Answer:

44

Step-by-step explanation:

if she had 10 left at the end and you add the other half from lunch which is 12, then that gives you 22. Since before lunch she had half (22), all you gotta do is add the other half which is 22. 22+22=44 and that's your answer.

6 0
4 years ago
Choose the appropriate pattern and use it to find the product: (p4−q4)(p4+q4).
sp2606 [1]

The expression can be solved by expanding the bracket and multiplying out the terms

(p^4-q^4)(p^4+q^4)\begin{gathered} =p^4(p^4+q^4)-q^4(p^4+q^4) \\ =p^8+p^4q^4-p^4q^4-q^8 \\ =p^8-q^8 \end{gathered}

Therefore, the expression can be simplified as;

p^8-q^8

Alternatively, using the theorem of difference of two squares, which is

a^2-b^2=(a-b)(a+b)

Hence,

p^8-q^8=(p^4)^2-(q^4)^2

7 0
1 year ago
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Setler79 [48]
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