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klemol [59]
3 years ago
14

Find the SURFACE AREA of this composite solid. Show work

Mathematics
1 answer:
bagirrra123 [75]3 years ago
4 0

Answer:

8

Step-by-step explanation:

4+4

6-6+8

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Factor the binomial using its GCF: 10x-15x^4
Igoryamba

Answer:

5x(2 - 3x³)

Step-by-step explanation:

10x-15x^4

The GCF( Greatest Common Factor) of 10x-15x^4 is 5x

Solve:

10x/5x = 2

-15^4/5x = -3x³

Final answer is

5x(2 - 3x³)

                         <u>Check</u>

5x(2 - 3x³)

distribute

5x(2) + 5x(-3x³)

10x - 15x^4

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4 years ago
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Which expression is equivalent to?
Anit [1.1K]

Answer:

the given expression is equivalent to

Step-by-step explanation:

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2 years ago
[Calculus] particle at rest question. Show steps, please!
Vinvika [58]

Answer:

E

Step-by-step explanation:

We are given that a particle's position along the x-axis at time <em>t </em>is modeled by:

x(t)=2t^3-21t^2+72t-53

And we want to determine at which time(s) <em>t</em> is the particle at rest.

If the particle is at rest, this suggests that its velocity at that time is 0.

Since are we given the position function, we can differentiate it to find the velocity function.

So, by differentiating both sides with respect to <em>t</em>, we acquire:

\displaystyle x^\prime(t)=v(t)=\frac{d}{dt}\big[2t^3-21t^2+72t-53\big]

Differentiate. So, our velocity function is:

v(t)=6t^2-42t+72

So, we will set the velocity to 0 and solve for <em>t</em>. Hence:

0=6t^2-42t+72

We can divide both sides by 6:

0=t^2-7t+12

Factoring yields:

(t-3)(t-4)=0

By the Zero Product Property:

t-3\text{ and } t-4=0

Hence:

t=3\text{ and } t=4

Therefore, at the 3rd and 4th seconds, the velocity of the particle is 0, impling that the particle is at rest.

Our answer is E.

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how many people bought the lunch

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