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pshichka [43]
4 years ago
9

One golfer's scores for the season are 88, 90, 86, 89, 96, and 85. Another

Mathematics
1 answer:
Allisa [31]4 years ago
6 0

Mean of the first golfer = 89

Mean of the second golfer = 87

Range of the first golfer = 11

Range of the second golfer = 8

Explanation:

First golfer scores 88, 90, 86, 89, 96 and 85.

Sum of the scores of first golfer = 88 + 90 + 86 + 89 + 96 + 85 = 534

Number of observation of first golfer = 6

\text {Mean} = \frac{\text {Sum of the observation}}{\text {Number of observation}}

Mean of the first golfer = \frac{534}{6}=89

Mean of the first golfer = 89

Range of the first golfer = Highest score – Lowest score

                                        = 96 – 85

Range of the first golfer = 11

Second golfer scores 91, 86, 88, 84, 90 and 83.

Sum of the scores of second golfer = 91 + 86 + 88 + 84 + 90 + 83 = 522

Number of observation of second golfer = 6

\text {Mean} = \frac{\text {Sum of the observation}}{\text {Number of observation}}

Mean of the second golfer = \frac{522}{6}=87

Mean of the second golfer = 87

Range of the second golfer = Highest score – Lowest score

                                              = 91 – 83

Range of the second golfer = 8

Comparing the golfer's skills:

Mean of first golfer is greater than Mean of second golfer.  (i.e. 89 > 87)

Range of first golfer is greater than Range of second golfer. (i.e. 11 > 8)

Thus, first golfer have more skills than second golfer.

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<img src="https://tex.z-dn.net/?f=4x%20%2B%203y%20%3D%200%20%5C%5C5y%20%2B%2053%20%3D%2011x%20%5C%5C%20" id="TexFormula1" title=
Anvisha [2.4K]

Answer:

x = 3, y = -4

Step-by-step explanation by substitution:

Solve the following system:

{4 x + 3 y = 0 | (equation 1)

5 y + 53 = 11 x | (equation 2)

Express the system in standard form:

{4 x + 3 y = 0 | (equation 1)

-(11 x) + 5 y = -53 | (equation 2)

Swap equation 1 with equation 2:

{-(11 x) + 5 y = -53 | (equation 1)

4 x + 3 y = 0 | (equation 2)

Add 4/11 × (equation 1) to equation 2:

{-(11 x) + 5 y = -53 | (equation 1)

0 x+(53 y)/11 = -212/11 | (equation 2)

Multiply equation 2 by 11/53:

{-(11 x) + 5 y = -53 | (equation 1)

0 x+y = -4 | (equation 2)

Subtract 5 × (equation 2) from equation 1:

{-(11 x)+0 y = -33 | (equation 1)

0 x+y = -4 | (equation 2)

Divide equation 1 by -11:

{x+0 y = 3 | (equation 1)

0 x+y = -4 | (equation 2)

Collect results:

Answer: {x = 3 , y = -4

_____________________________________

Solve the following system:

{4 x + 3 y = 0

5 y + 53 = 11 x

Hint: | Choose an equation and a variable to solve for.

In the first equation, look to solve for x:

{4 x + 3 y = 0

5 y + 53 = 11 x

Hint: | Isolate terms with x to the left hand side.

Subtract 3 y from both sides:

{4 x = -3 y

5 y + 53 = 11 x

Hint: | Solve for x.

Divide both sides by 4:

{x = -(3 y)/4

5 y + 53 = 11 x

Hint: | Perform a substitution.

Substitute x = -(3 y)/4 into the second equation:

{x = -(3 y)/4

5 y + 53 = -(33 y)/4

Hint: | Choose an equation and a variable to solve for.

In the second equation, look to solve for y:

{x = -(3 y)/4

5 y + 53 = -(33 y)/4

Hint: | Isolate y to the left hand side.

Subtract 53 - (33 y)/4 from both sides:

{x = -(3 y)/4

(53 y)/4 = -53

Hint: | Solve for y.

Multiply both sides by 4/53:

{x = -(3 y)/4

y = -4

Hint: | Perform a back substitution.

Substitute y = -4 into the first equation:

Answer: {x = 3 , y = -4

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