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4 years ago

5

Find the perimeter and area of a rectangle whose length is (x + 1) and whose width is (x - 3). Express your answer in terms of x

. With explanation if you can plz and thx

1 answer:

joja [24]4 years ago

6 0

Answer:

Perimeter=2L+2w

P=2(x+1)+2(x-3)

P=2x+2+2x-6

P=4x-4

Area=Lxw

A=(x+1)x(x-3)

A=x^2-3x+x-3

A=x^2-2x-3

Step-by-step explanation:

I don't have one :v

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Answer:

Lateral Area = 176 cm²

Step-by-step explanation:

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Where,

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Breadth (b) = 4 cm

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CaHeK987 [17]

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3 years ago

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3 years ago

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ruslelena [56]

Answer:

Two other possible measure ments of AD and AE are

(a) Let AD = 4 units and AE = 6 units.

(b )Let AD = 2 units and AE = 3 units,

Step-by-step explanation:

In ΔABC, given

AB = 8 units, BC = 9 units, AC = 12 units,

D is on AB and E is on AC

Now, when AD = 6 and AE = 9, both ΔABC and ΔADE are similar.

Also, DB = 8 units - 6 units = 2 units,

EC = 12 units - 9 units = 3 units

⇒ $\frac{AD}{DB} = \frac{AE}{EC} = 3$

To adjust the points D and E in such a way, triangles REMAIN SIMILAR.

(a) Let AD = 4 units and AE = 6 units

Then, DB = 8 units - 4 units = 4 units,

EC = 12 units - 6 units = 6 units

⇒ $\frac{AD}{DB} = \frac{4}{4} = 1 , \\ \frac{AE}{EC} = \frac{6}{6} = 1$

⇒ $\frac{AD}{DB} = \frac{AE}{EC} = 1$

Hence, ΔABC and ΔADE are similar.

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⇒ $\frac{AD}{DB} = \frac{AE}{EC} =\frac{1}{3}$

Hence, ΔABC and ΔADE are similar.

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3 years ago