The Lagrangian for this function and the given constraints is

which has partial derivatives (set equal to 0) satisfying

This is a fairly standard linear system. Solving yields Lagrange multipliers of

and

, and at the same time we find only one critical point at

.
Check the Hessian for

, given by


is positive definite, since

for any vector

, which means

attains a minimum value of

at

. There is no maximum over the given constraints.
It will hit the ground after 3.499 seconds.
To solve this you first have to find the value of h(0) in this equation. That is the height from which it was dropped.
You can input any of the points into the equation and solve for the missing part. You will get 60 for the height.
The use the quadratic formula to see that it reaches the ground after 3.499 seconds.
Answer:
Given system of equations:

To solve by substitution, equate the equations and solve for x:

Therefore, the x-values of the solution are
and
.
To find the y-values of the solution, substitute the found values of x into the functions:




Therefore, the solutions to the given system of equations are:
and 