Answer:
Required Probability = 0.97062
Step-by-step explanation:
We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.
Let X = weight of the newborn baby, so X ~ N(
)
The standard normal z distribution is given by;
Z = 
~ N(0,1)
Now, probability that the weight will be less than 5026 grams = P(X < 5026)
P(X < 5026) = P( < 
) = P(Z < 1.89) = 0.97062
Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .
Answer:
look from the tan A angle , the opposite is 28 and adjacent is 45
7 1/12 - 2 3/4
First we have to change mixed numbers to improper fractions
7 1/12 = 7 x 12 + 1 = 85 85/12
2 3/4 = 2 x 4 + 3 = 11 11/4
85/12 - 11/4
Now we need to find the LCD (least common denominator) for 4 and 12
4, 8, 12
12
12 is our LCD, so it becomes our new denominator
85/12 would stay the same because the denominator wasn't changed but for 11/4 our new denominator is 12, so our fraction will change.
11/4 = 33/12
4 goes into 12, 3 times. What you do to the bottom, you do to the top.
3 x 11 = 33
3 x 4 = 12
So, our new fraction is 33/12. Now we subtract
85/12 - 33/12 = 52/12
Now we convert back to a mixed number
52 ÷ 12 = 4 4/12 reduce
4 1/3
Hope this helps.
<h2>
Answer:</h2><h2>D. 4b + 6</h2><h2 /><h2>Hope this helps!!</h2>
Answer:
Miguel cabrera
Step-by-step explanation:
Given that :
Miguel cabrera's batting average = 0.33
Mike trout's batting average = 0.326
The average for both players was obtained during the same season:
Hence. Comparing their respective averages,
0.33 = 0.330
0.330 > 0.326
Hence, Miguel Cabrera's batting average is higher than that of Mike trout
