It is easy <span>for your audience to see what you are describing. Graphs and diagrams help get any point across clearer for mathematics :)</span>
        
             
        
        
        
You have two choices.
The minimum possible cost to operate your bat factory for a day is $390,
and there are two quantities of bats that both cost that much.
One possibility:  
                   Produce no bats at all per day.  Zero.  Nada.  None. 
                    Cost = 0.06(0)²  -  7.2(0)  +  390  =  $390 per day.
The other choice:
                   Produce  120 bats per day.
                   Cost = 0.06(120²)  -  7.2(120)  +  390
                          = 0.06(14,400)  -  7.2(120)  +  390
                          =      864          -      864      +  390
                          =      $390  per day.
If you produce any other number of bats in a day ... more than zero 
but not 120 ... then it will cost you more than $390 to operate the factory 
that day.
        
             
        
        
        
Answer:

is the required polynomial with degree 3 and p ( 7 ) = 0 
Step-by-step explanation:
Given:
p ( 7 ) = 0
To Find:
p ( x ) = ?
Solution:
Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.
Therefore zero's of the polynomial is seven i.e 7
Degree : Highest raise to power in the polynomial is the degree of the polynomial
We have the identity,

Take a = x
         b = 7
Substitute in the identity we get

Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.
p ( 7 ) = 7³ - 21×7² + 147×7 - 7³
p ( 7 ) = 0

 
        
             
        
        
        
Answer:
5.86
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:Theo worked for 10.5 hours.
Kade worked for 16.5 hours
Step-by-step explanation: