What other compatible numbers could you use for 428 and 286

1 answer:

4 0

How about raising 286 up by 14 to 300 and compensating by lowering 428 by the same 14 Since I know that 14 + 14 is 28 then 28-14 is 14
So 428 - 14 = 414
So now I have 414 + 300 which I can do mentally - the answer is 714 and is also the answer to the original problem 428 + 286

Compensation works very well - bring one number up or down to a rounded number and compensate by doing the opposite to the other - instead of 199 + 457 - try 200 + 456
Same answer and because one of the numbers is nicely rounded, it is easy to add the other.

One more: 207 + 182 becomes 200 + 189 =389 I lowered one by 7 and raised the other one by the same 7.

You might be interested in

A line of best fit was drawn for 5 data points. what is the maximum number of these data points that may not actually be on the

jenyasd209 [6]

[b.3] ^_^
hopefully i helped (0-0)

4 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST FOR THE BEST ANSWER. PLEASE SHOW FULL SOLUTIONS. THANK YOU AND GOD BLESS. THE QUESTION IS ATTACHED. :)

Anuta_ua [19.1K]

9514 1404 393

Answer:

(x, y) = (34/5, -4/5) = (6.8, -0.8)

Step-by-step explanation:

Subtract the first equation from the second to eliminate x.

$\left(\dfrac{x}{3}-\dfrac{y}{2}\right)-\left(\dfrac{x-5}{3}+\dfrac{y+2}{3}\right)=\left(\dfrac{8}{3}\right)-(1)\\\\y\left(-\dfrac{1}{2}-\dfrac{1}{3}\right)+\left(\dfrac{5}{3}-\dfrac{2}{3}\right)=\dfrac{5}{3} \qquad\text{partially simplify}\\\\-\dfrac{5}{6}y=\dfrac{2}{3} \qquad\text{subtract 1}\\\\y=-\dfrac{4}{5} \qquad\text{multiply by $-\dfrac{6}{5}$}$

Substituting for y in the second equation, we can find x.

$\dfrac{x}{3}-\dfrac{1}{2}\left(-\dfrac{4}{5}\right)=\dfrac{8}{3}\\\\5x +6=40 \qquad\text{multiply by 15}\\\\5x=34\qquad\text{subtract 6}\\\\x=\dfrac{34}{5}$