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Marysya12 [62]
3 years ago
8

Is b - 12 = - 5; 17 solution

Mathematics
1 answer:
Pani-rosa [81]3 years ago
7 0
No the answer to the solution would be 7
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erica [24]

Answer:

your right good job

Step-by-step explanation:

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tankabanditka [31]
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Solve each equation y-6.72=253
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You just need to have the variable by itself, so move the -6.72 to the other side (that will make it +6.72)
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3 years ago
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What is the probability of getting blue and green on a spinner that is 3/10 and 1/5 blue
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5 0
3 years ago
Daily high temperatures in the city of Houston for the last week have been: 90, 93, 90 92, 90, 88, 98 (yesterday).
vesna_86 [32]

Answer:

  1. The answer or forecast for temperature using a three-day moving average =
  2. The answer or forecast for temperature using a three-day moving average =
  3. The mean absolute deviation based on a two-day moving average, covering all days =  

Step-by-step explanation:

1. Three-point averages are calculated by taking a number in the series with the previous and next numbers and averaging the three of them.

Step I - Calculate the three series of succession of numbers form the data and find the average of each of them:

A) (90 + 93 +90)/3 = 91.00

B) (93 + 92 + 90)/3 = 91.67

C) (90 + 92 +90)/3 = 90.67

D) (92 + 90 + 88)/3 = 90.00

E) (90 + 88 + 98)/3 = 92.00

So our series approximated to the nearest whole number is:

91, 92, 91, 90, 92

STEP II

 

From the series above the highest temperature today is unpredictable because the series is irregular. It went from 91 to 92, then it dropped to 90 and came back to 92.

             

2. Using a two day moving average we have

STEP I .  

Calculate the moving averages

           

A) (90+93)/2 = 91.50

B) (93 + 90)/2 = 91.50

C) (90 + 92)/2 = 91.00

D) (92 +90)/2 = 91.00

E) (90 + 88)/2 = 89.00

F) (88 + 98)/2 = 93.00

STEP II

The temperature also cannot be predicted because of the irregular series.

3. Calculating the Mean Absolute Deviation based on a two-day moving average

The formula for MAD = (∑|x_{i} - \frac{}{x}|)/n

STEP I

To find the mean absolute deviation of the data, start by finding the mean of the data set.

Mean of the data set =

(91.50 + 91.50 + 91.00 +  91.00 + 89.00 +93.00)/6

Mean = 91.17

STEP II

Get the distance between the data point and the mean:

  1. 91.50-91.17=0.33
  2. 91.50-91.17= 0.33
  3. 91.00-91.17= -0.17
  4. 91.00-91.17= -0.17
  5. 89.00-91.17= -2.17
  6. 90.00-91.17= -1.17

STEP II

Add all the distances together

0.33 + 0.33 - 0.17 - 0.17 - 2.17 - 1.17 = -3.02

STEP III

Divide the the sum by data points

-3.02/6

= -0.50

So on average the temperatures were <em>-0.50</em> from the mean.

Cheers!

3 0
3 years ago
Read 2 more answers
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