Work shown above! Answers are (3√2, π/4) and (3√2, 5π/4)
Answer:
We fail to reject the null hypothesis because -1.7678 does not fall inside the rejection region {z | z < -1.96 or z >1.96}
Step-by-step explanation:
We have that the machine will fill bottles according to a normally distributed process, let's say is a random variable that represents this process. We know that has a mean of 47 fluid ounces and a standard deviation of 0.4 fluid ounces. We have a sample of n = 50 bottles and the observed value .
We want to test
vs (two-tailed alternative)
We have n = 50 large enough, and the point estimator of the mean , which is normally distributed with the same mean than , i.e., , and with standard deviation given by . Therefore, our test statistic is
and
.
As we want a significance level of 0.05, we should find the values and , i.e., the 2.5th quantile and the 97.5th quantile for the standard normal distribution. These values are -1.96 and 1.96 respectively. The rejection region is given by {z | z < -1.96 or z >1.96}. We fail to reject the null hypothesis because -1.7678 does not fall inside the rejection region.
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Answer:
Answer: k must be 5/2 or 1
Step-by-step explanation:
» Factorise the equation:
Answer:
The negative three times negative five