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LekaFEV [45]
4 years ago
10

19 multiplicado por 473

Mathematics
2 answers:
trasher [3.6K]4 years ago
7 0
473×19=8987 ☺☺☺☺☺☺☺☺☺☺☺
Anna [14]4 years ago
6 0
473 x 19 = 8987. Your welcome and i no speak espanol
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Can someone answer quick!!! ​
galben [10]

Answer:

Step-by-step explanation:

answer what?

8 0
3 years ago
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The SAT scores have an average of 1200 with a standard deviation of 60. A sample of 36 scores is selected. a) What is the probab
erastova [34]

Answer:

the probability that the sample mean will be larger than 1224 is  0.0082

Step-by-step explanation:

Given that:

The SAT scores have an average of 1200

with a  standard deviation of 60

also; a sample of 36 scores is selected

The objective is to determine  the probability that the sample mean will be larger than 1224

Assuming X to be the random variable that represents the SAT score of each student.

This implies that  ;

S \sim N ( 1200,60)

the probability that the sample mean will be larger than 1224 will now be:

P(\overline X > 1224) = P(\dfrac{\overline X - \mu }{\dfrac{\sigma}{\sqrt{n}} }> \dfrac{}{}\dfrac{1224- \mu }{\dfrac{\sigma}{\sqrt{n}} })

P(\overline X > 1224) = P(Z > \dfrac{1224- 1200 }{\dfrac{60}{\sqrt{36}} })

P(\overline X > 1224) = P(Z > \dfrac{24 }{\dfrac{60}{6} })

P(\overline X > 1224) = P(Z > \dfrac{24 }{10} })

P(\overline X > 1224) = P(Z > 2.4 })

P(\overline X > 1224) =1 -  P(Z \leq 2.4 })

From Excel Table ; Using the formula (=NORMDIST(2.4))

P(\overline X > 1224) = 1 -  0.9918

P(\overline X > 1224) = 0.0082

Hence;  the probability that the sample mean will be larger than 1224 is  0.0082

4 0
4 years ago
Pls help if I don’t finish today mom will hurt me
kherson [118]

Answer:

We conclude that:

  • g(10) = 8

Step-by-step explanation:

First, we need to clear some concepts on how to fetch input and output from the function graph.

Determining the y-intercept:

We know that the y-intercept of the graph function can be determined by setting x = 0 and determining the corresponding y-value.

From the graph it is clear that x = 0, the value of y = 5. In other words, the graph intersects the y-axis at y = 5.

Therefore, the y-intercept of the graph is (0, 5).

Thus,

  • g(0) = 5

Determining the x-intercept:

We know that the x-intercept of the graph function can be determined by setting y = 0 and determining the corresponding x-value.

From the graph, it is clear that y = 0, the value of x = -10. In other words, the graph intersects the x-axis at x = -10.

Therefore, the x-intercept of the graph is (-10, 0).

Thus,

  • g(-10) = 0

Determining g(10):

From the graph, it is clearly visible that at x = 10, the value of the function output y = 8.

In other words,

  • at x = 10, g(10) = 8

Therefore, we conclude that:

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5 0
3 years ago
Rainfall collected in a rain gauge was found to be 2.3 cm when rounded to the nearest tenth of a centimeter.
Korolek [52]

Answer:

(a). 2.251 cm , 2.349 cm, 2.295 cm

(b). 0.023 meters.

Step-by-step explanation:

(a). We are asked to to choose the options that shows the actual measurement of the rainfall.

Since the rounded figure is 2.3 cm, this means that either the tenths digit is 3 with hundredths digit less than 5, or tenths digit is 2 with hundredths digit greater than or equal to 5.

Let us check our given choices one by one.

2.251\text{ cm}\approx 2.3\text{ cm}

2.349\text{ cm}\approx 2.3\text{ cm}

2.352\text{ cm}\approx 2.4\text{ cm}

2.295\text{ cm}\approx 2.3\text{ cm}

Therefore, the correct choices are 2.251 cm , 2.349 cm  and 2.295 cm.

(b) We know that 1 cm equals 0.01 meters.

To convert 2.3 cm to meters, we will multiply 2.3 by 0.01.

2.3\text{ cm}=2.3\text{ cm}\times \frac{0.01\text{ meters}}{\text{cm}}

2.3\text{ cm}=0.023\text{ meters}

Therefore, the rounded measurement of rain would be 0.023 meters.

8 0
4 years ago
At the fast pack shiping. The employees can unload 25 trucks in 5 hours which of the following is a correct unit rate for this s
Natasha2012 [34]

Answer:

5 trucks per hour

Step-by-step explanation:

25 trucks ÷ 5

5 hours ÷ 5

= 5 trucks per hour

3 0
4 years ago
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