If RT is greater than BA, which correctly compares c and s

Mathematics

1 answer:

Fofino [41]3 years ago

3 0

Answer:

Step-by-step explanation:

The answer is B

By the converse of the hinge theorem, mC = mS. FALSE. EITHER ANGLE IS LARGER THAN THE OTHER

By the hinge theorem,TS > AC. FALSE. CONGRUENT SIDES BASED ON THE GIVEN IMAGE.

By the converse of the hinge theorem, mS > mC.the statement that is true

By the hinge theorem, BA = RT. FALSE. 3RD SIDE OF EITHER TRIANGLE WILL BE LONGER THAN THE OTHER.

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Can someone please help me

nadya68 [22]

Answer:

Right option is B.

Step-by-step explanation:

$\sf \longrightarrow \frac{ \sec x \sin( - x) + \tan( - x) }{1 + \sec( - x) } \\ \\ \sf \longrightarrow \frac{ \sec x( - \sin x) - \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - \frac{1}{ \cos x } \times \sin x - \tan x }{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - \tan x - \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ - 2 \tan x}{1 + \sec x} \\ \\ \sf \longrightarrow \frac{ \frac{ - 2 \sin x}{ \cos x} }{1 + \frac{1}{ \cos x} } \\ \\ \sf \longrightarrow \frac{ \frac{ - 2 \sin x}{ \cos x} }{ \frac{ \cos x + 1}{ \cos x} } \\ \\ \boxed{ \sf{\longrightarrow \frac{ - 2 \sin x}{ \cos x + 1} }}$